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Leokris [45]
3 years ago
7

Each of two identical objects carries a net charge. The objects are made from conducting material. One of them is attracted to a

positively charged ebonite rod, and the other is repelled by the rod. After the objects are touched together, it is found that they are each repelled by the rod. What can be concluded about the initial charges on the objects?
a) initially, both objects are positive, with both charges having the same magnitude.
b) Initially both objects are negative, with both charges having the same magnitude.
c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.
d) Initially one object is positive and one is negative, with the negative charge having a greater magnitude than the positive charge.
Physics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

It can be concluded that:

c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.

Explanation:

There is the property of charges by virtue of which like charges repel each other and unlike charges attract each other.

Given that,

Initially, one of the object is attracted to positively charged ebonite rod, therefore, it must have negative charge initially and the other is repelled by the rod, therefore, it must have positive charge initially.

When the two objects touched together, there is a redistribution of charges on them, such that, the net charge on both the objects distributes equally on both.

Since, it is found that they are each repelled by the rod after the objects touched each other, it means they both acquire positive charges.

Both the objects acquire positive charge implies that the net charge on the two objects, i.e., the sum of charges on the two objects, must be positive before they were touched which means that the object with the positive charge had charge greater in magnitude.

So the correct conclusion is:

c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.

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                     = \frac{2 (1000 W/m^{2})(5.5 \times 10^{3} m)^{2}}{3 \times 10^{8} m/s}

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8 0
3 years ago
A​ heavy-duty shock absorber is compressed 4 cm from its equilibrium position by a mass of 700nbspkg. How much work is required
tia_tia [17]

Answer:

Explanation:

A mass of 700 kg will exert a force of

700 x 9.8

= 6860 N.

Amount of compression x = 4 cm

= 4 x 10⁻² m

Force constant K = force of compression / compression

= 6860 / 4 x 10⁻²

= 1715 x 10² Nm⁻¹.

Let us take compression of r at any moment

Restoring force by spring

= k r

Force required to compress = kr

Let it is compressed  by small length dr during which force will remain constant.

Work done

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= kr dr

Work done to compress by length d

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Integrating on both sides

W  = \int\limits^{-4}_0 {kr} \, dr

= [ kr²/2]₀^-4

= 1/2 kX16X10⁻⁴

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2 years ago
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Explanation:

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2 years ago
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Answer:

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In this problem, we have:

A. 100 ounces of water  --> scalar (this is a volume, which has only a magnitude)

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