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Leokris [45]
4 years ago
7

Each of two identical objects carries a net charge. The objects are made from conducting material. One of them is attracted to a

positively charged ebonite rod, and the other is repelled by the rod. After the objects are touched together, it is found that they are each repelled by the rod. What can be concluded about the initial charges on the objects?
a) initially, both objects are positive, with both charges having the same magnitude.
b) Initially both objects are negative, with both charges having the same magnitude.
c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.
d) Initially one object is positive and one is negative, with the negative charge having a greater magnitude than the positive charge.
Physics
1 answer:
WINSTONCH [101]4 years ago
4 0

Answer:

It can be concluded that:

c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.

Explanation:

There is the property of charges by virtue of which like charges repel each other and unlike charges attract each other.

Given that,

Initially, one of the object is attracted to positively charged ebonite rod, therefore, it must have negative charge initially and the other is repelled by the rod, therefore, it must have positive charge initially.

When the two objects touched together, there is a redistribution of charges on them, such that, the net charge on both the objects distributes equally on both.

Since, it is found that they are each repelled by the rod after the objects touched each other, it means they both acquire positive charges.

Both the objects acquire positive charge implies that the net charge on the two objects, i.e., the sum of charges on the two objects, must be positive before they were touched which means that the object with the positive charge had charge greater in magnitude.

So the correct conclusion is:

c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.

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A<span>ll scientific endeavors involve experimentation.</span>
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The USC Trojan football team bus is heading to an away game, traveling on a long, straight road at a constant speed of 28.0 m/s.
Ugo [173]

Answer:

a. 17.34 s. b. 104.51 m c. -7.16 m/s²

Explanation:

a. The distance, d moved by the car at constant speed v = 6.00 m/s in time t which they collide is d = vt. The distance d' moved by the bus from its initial position 70 m away from the car with a constant velocity u = 28.0 m/s and deceleration a = -3.00 m/s² is d' = 70 + ut + 1/2at².

At collision, s = d

vt = 70 + ut + 1/2at²

substituting the values of the variables, we have

6t = 70 + 28t + 1/2(-3)t²

6t = 70 + 28t - 1.5t²

collecting like terms, we have

1.5t² + 6t - 28t - 70 = 0

1.5t² - 22t - 70 = 0

using the quadratic formula to find t, we have

t = \frac{-(-22) +/- \sqrt{(-22)^{2} - 4 X -70 X 1.5} }{2 X 1.5} \\t = \frac{22 +/- \sqrt{484 + 420} }{3} \\\\t = \frac{22 +/- \sqrt{904} }{3} \\\\t = \frac{22 +/- 30.01 }{3} \\\\t = \frac{22 - 30.01 }{3} or \frac{22 + 30.01 }{3} \\t = \frac{-8.01 }{3} or \frac{52.01 }{3} \\\\t = -2.67 s or 17.34 s

We take the positive value.

So t = 17.34 s.

So, 17.34 s elapses before the bus and car collide.

b. Since the distance covered by the bus is d' = 70 + ut + 1/2at², this is how far down the road the collision occurs.

Substituting the values of the variables, we have

d' = 70 + 28 m/s × 17.34 s + 1/2(-3 m/s²)(17.34)²

d' = 70 + 485.52 - 451.01

d'= 104.51 m

c. To just avoid the collision, the bus must decelerate in the distance of 104.51 m from the car to the speed of the car. So using

v² = u² + 2ad' where v = 6.00 m/s, u = 28.0 m/s and d' = 104.51 m

the acceleration is thus

a = (v² - u²)/d'

a = ((6 m/s)² - (28 m/s)²)/104.51 m

a = (36 m²/s² - 784 m²/s²)/104.51 m

a = -748 m²/s² ÷ 104.51 m

a = -7.16 m/s²

3 0
3 years ago
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mariarad [96]
Hello,

The answer is option D "<span>Energy is conserved".

Reason:

The answer to this question is option D because it seems to be the best fit. Its not option A or B because energy cannot be created nor destroyed it only can be transformed into another type of energy. It shouldn't be C because energy is not always increasing because potential energy is the amount a energy that is in a object THATS NOT MOVING....therefore your answer is option D.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonpotrit</span>
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Ede4ka [16]

Answer:

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Explanation:

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7 0
3 years ago
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