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Leokris [45]
3 years ago
7

Each of two identical objects carries a net charge. The objects are made from conducting material. One of them is attracted to a

positively charged ebonite rod, and the other is repelled by the rod. After the objects are touched together, it is found that they are each repelled by the rod. What can be concluded about the initial charges on the objects?
a) initially, both objects are positive, with both charges having the same magnitude.
b) Initially both objects are negative, with both charges having the same magnitude.
c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.
d) Initially one object is positive and one is negative, with the negative charge having a greater magnitude than the positive charge.
Physics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

It can be concluded that:

c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.

Explanation:

There is the property of charges by virtue of which like charges repel each other and unlike charges attract each other.

Given that,

Initially, one of the object is attracted to positively charged ebonite rod, therefore, it must have negative charge initially and the other is repelled by the rod, therefore, it must have positive charge initially.

When the two objects touched together, there is a redistribution of charges on them, such that, the net charge on both the objects distributes equally on both.

Since, it is found that they are each repelled by the rod after the objects touched each other, it means they both acquire positive charges.

Both the objects acquire positive charge implies that the net charge on the two objects, i.e., the sum of charges on the two objects, must be positive before they were touched which means that the object with the positive charge had charge greater in magnitude.

So the correct conclusion is:

c) Initially one object is positive and one is negative, with the positive charge having a greater magnitude than the negative charge.

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The maximum pressure variations the human ear can withstand are about how much above and below atmospheric pressure?
Crank

The maximum pressure variations the human ear can withstand  above and below atmospheric pressure is around 30 pa. the normal atmospheric pressure is around 101325 pa. hence the variation in the maximum pressure for human ear is very small as compared to the atmospheric pressure. if the ear is exposed to a pressure greater than this , it can cause permanent damage to the ear.

4 0
3 years ago
How do I do number 8, plz respond quick, I have a big unit test on this and I’m rocking a 65 science average rn. Thank you for t
xxTIMURxx [149]

Answer:

3 is the correct answer for number 8

6 0
3 years ago
Read 2 more answers
A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student
castortr0y [4]

Answer:

5x10^-3

Explanation:

Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.

Hooke's Law can be represented as

<h3> F = kx, </h3>

<em>where F is the force </em>

<em>            k is the spring constant</em>

<em>            x is the extension of the material </em>

<em />

Plug values in the equation

Step 1 find the original extension

0.045 = (400)x

x = 1.125x 10^-4 m d

Step 2 find the new extension

0.045+2 = 400(x)

2.045 = 400x

x = 5.1125x10^-3

Step 3 subtract the new extension with original

Total extension of the spring =  5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3

8 0
3 years ago
It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used
stepladder [879]

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

a_{c} = rω²

ω² = a_{c} / r

ω = √( a_{c} / r )

where r is the radius of the cylinder

ω is the angular velocity

given that; the centripetal acceleration equal to the acceleration of gravity a a_{c}  = g = 9.8 m/s²

so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

7 0
3 years ago
1. Which of the following is not an acceptable Physical Education activity?
Dmitrij [34]
The answer is A

Explanation:
Vacuuming doesn’t involve a lot of physical movements.
3 0
3 years ago
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