Question

An Alaskan rescue plane traveling 45 m/sdrops a package of emergency rations froma height of 145 m to a stranded party of reese (enr647) – Homework 3, 2d motion 19-20 – dowd – (McdanielMPHY119203)3explorers.The acceleration of gravity is 9.8 m/s2.Where does the package strike the groundrelative to the point directly below where it

Answer 1

Answer:

package will strike at a distance of 244.7  m

Explanation:

Given data;

Velocity of plane 45 m/s

Acceleration due to gravity 9.8 m/s^2

horizontal component of plane velocity is ux = 45 m/s

vertical component is zero

in the same way

ay = - 9.8  m/s^2

ax = .0 m/s^2

motion in y direction = -145 m

from equation of motion time of flight is

$s = ut + \frac{1}{2} at^2$

$-145 = 0 + \frac{1}{2} (-9.8) t^2$

solving for t  we get

t = 5.439 sec

Motion in x direction

$s = ut + \frac{1}{2} at^2$

$= (45 \times 5.43) + \frac{1}{2} (0) 5.43^2$

s = 244.79 m

Therefore package will strike at a distance of 244.7  m