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Nimfa-mama [501]
2 years ago
13

A common black ant discovers a piece of bread 85 cm east of the entrance of her nest. If the ant carries 10 bits of bread back t

o her nest on separate trips before moving on to other chores, what distance did she travel after discovering the bread? What was her displacement from the nest after dropping up the last bit of bread?
Physics
1 answer:
babunello [35]2 years ago
5 0

Answer:

19 x 85 = 1,615 for distance. Displacement is 0

Explanation:

The total distance traveled by the ant in 9 round trips and one 1/2 trip, or 19 one bash way trips: 19 x 85cm = 1615cm. The displacement of the ant after the tenth trip is 0 cm ( the displacement origin is the nest.)

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Sound waves travel at the rate of 343 m/s at 20°C. If a man standing 450 meters away from the wall of a canyon yells, “Hello,” h
nekit [7.7K]

Answer:

2.62seconds

Explanation:

Speed is defined as the ratio of the distance covered by a body with respect to time.

Speed v = Distance (s)/Time (t)

For a traveling sound wave, the distance between the source of a sound and the reflector is '2S'.

Speed v = 2 × distance (S)/Time (T)

V = 2S/t

2S = vt

Given speed of the wave = 342m/s

Distance covered = 450m

t = 2S/v

t = (2×450)/343

t = 900/343

t = 2.62seconds

It will take him 2.62seconds for him to hear his own voice echo off of the wall.

5 0
2 years ago
Read 2 more answers
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

3 0
3 years ago
What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?
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Kinetic energy= 1/2 m v^2

so... 1/2(1350)(12^2)

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7 0
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How is it technically correct to say that a car making a u-turn can have a constant speed but cannot have a constant velocity?
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During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.

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During which stage of the cell cycle does the cell condense chromosomes and break down the nuclear envelope? Group of answer cho
Natalka [10]

Answer:

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During the Prophase

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