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Nimfa-mama [501]
2 years ago
13

A common black ant discovers a piece of bread 85 cm east of the entrance of her nest. If the ant carries 10 bits of bread back t

o her nest on separate trips before moving on to other chores, what distance did she travel after discovering the bread? What was her displacement from the nest after dropping up the last bit of bread?
Physics
1 answer:
babunello [35]2 years ago
5 0

Answer:

19 x 85 = 1,615 for distance. Displacement is 0

Explanation:

The total distance traveled by the ant in 9 round trips and one 1/2 trip, or 19 one bash way trips: 19 x 85cm = 1615cm. The displacement of the ant after the tenth trip is 0 cm ( the displacement origin is the nest.)

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lbvjy [14]

Answer:

The value is T_c  =  12 .1 ^oC

Explanation:

From the question we are told that

The mass of the ice cube is m_i  =  7.50 *10^{-3} \  kg

The temperature of the ice cube is T_i = 0^o C

The mass of the copper cube is m_c  =  0.540 \  kg

The final temperature of both substance is T_f  =  0^oC

Generally form the law of thermal energy conservation,

The heat lost by the copper cube = heat gained by the ice cube

Generally the heat lost by the copper cube is mathematically represented as

Q =  m_c  *  c_c *  [T_c  -  T_f ]

The specific heat of copper is c_c  = 385J/kg \cdot  ^oC

Generally the heat gained by the ice cube is mathematically represented as

Q_1 =  m_i * L

Here L is the latent heat of fusion of the ice with value L  =  3.34 * 10^{5} J/kg

So

Q_1 =  7.50 *10^{-3} * 3.34 * 10^{5}

=> Q_1 =  2505 \ J

So

2505  =  0.540  *  385 *  [T_c  - 0 ]

=>    T_c  =  12 .1 ^oC

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Answer:

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