The combustion reaction of hexane:
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2
12 * x = 18.4 * 2
12 x = 36.8
x = 36.8 / 12
x = 3.067 moles of CO2
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Answer: kindly check explanation
Explanation:
Given the following :
Measured density of copper block:
8.6+/-0.2 g/cm3
True density = 8.96g/cm3
Standard deviation = 0.4g/cm
a. What is the high and low number of the confidence interval range?
High : 8.6 + 0.2 g/cm3 = 8.8g/cm³
Low : 8.6 - 0.2 g/cm3 = 8.4g/cm³
Does the true value fall within the confidence interval? NO
Actual density = 8.96g/cm³ doses not lie in between (8.4 - 8.8)g/cm³
B.) High and low of the standard deviation range?
High = 8.6 + 0.4 = 9.0g/cm³
Low = 8.6 - 0.4 = 8.2g/cm³
Value falls within range of the true density value of copper block.
8.96g/cm³ falls in-between (8.2-9.0)g/cm³
Find the [OH-] in the solution. The pH is 9.5, so the pOH is 14 - 9.5 = 4.5.
[OH-] = 10^-4.5 M
Now use the dilution equation to find the new [OH-] after the volume is reduced from 150 mL to 50 mL:
M1V1 = M2V2
M1 = 10^-4.5 M
V1 = 150 mL
M2 = ?
V2 = 50 mL
(10^-4.5)(150) = M2(50)
M2 = 9.5 x 10^-5 M ≈ 1 • 10^-4 (We can only use one sig fig, because the pH was given to one decimal place.)
Now use this [OH-] to find pOH:
pOH = -log(1 x 10^-4) = 4.0
14 - pOH = pH, so the expected pH for the new solution is 10.
In order to create a cation, one first needs to understand that a cation is an atom with excessive positive particles (proton) as compared to negative particles (electrons). Hence, a cation is always positively charge.
From the image simulating the orbital, proton and neutron are represented by either of the red or yellow ball respectively since both particles occupy the innermost part of the atom. The electron is usually revolves in the orbitals and hence, is represented by the blue ball.
Assuming that the proton is represented by the red ball, all that is required to create a cation would be to have more red ball in the nucleus than blue balls outside the nucleus.
More on the charged atoms can be found here: brainly.com/question/9264485
