Hey there!
theoretical yield = (87* 100 ) / 60 = 145 g of phosphorous pentachloride
the reaction for this process is :
molar mass P2O5 => 239.2125 g/mol
molar mass P4 => 123.90 g/mol
molar mass Cl2 => 70.9060 g/mol
P4 + 5 Cl2 --------------> 2 P2Cl5
moles of P2O5 :
145 g / 239.2125 => 0.6062 moles of P2O5
Therefore:
moles of P4 = 0.6062 mol / 2 => 0.3031 moles
moles of Cl2 = 5/2 * 0.6062 mol = 1.5154 moles
mass of P4 ( phosphours ) = 0.3031 mol * 123.90 => 37.554 grams
mass of Cl2 ( chlorine ) = 1.5154 mol * 70.9060 => 107.45 grams
Hope That helps!
Answer:
Chocolate melts and becomes really sticky once heated.
Add-on:
hope that helped at all.
Ca(OH)₂ = Ca²⁺ + 2OH⁻
[OH⁻]=2c{Ca(OH)₂}
pH=14+lg[OH⁻]
pH=14+lg(2c{Ca(OH)₂})
pH=14+lg(2*0.0075)=12.18
The correct answer choice from the statement above about investigated factors from lab results is :
Students who spend less time studying after school get lower math grade
Option D is the correct answer
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So therefore, The correct answer choice from the statement above about investigated factors from lab results is :
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Answer:
101.56 of H₂O
Explanation:
The balanced equation for the reaction is given below:
CH₄ + 2O₂ —> CO₂ + 2H₂O
Next, we shall determine the mass of CH₄ that reacted and the mass of H₂O produced from the balanced equation. This is illustrated below:
Molar mass of CH₄ = 12 + (4×1.01)
= 12 + 4.04
= 16.04 g/mol
Mass of CH₄ from the balanced equation = 1 × 16.04 = 16.04 g
Molar mass of H₂O = (2×1.01) + 16
= 2.02 + 16
= 18.02 g/mol
Mass of H₂O from the balanced equation = 2 × 18.02 = 36.04g
SUMMARY:
From the balanced equation above,
16.04 g of CH₄ reacted to produce 36.04 g of H₂O.
Finally, we shall determine the mass of water, H₂O produced by the reaction of 45.2 g of methane, CH₄. This can be obtained as illustrated below:
From the balanced equation above,
16.04 g of CH₄ reacted to produce 36.04 g of H₂O.
Therefore 45.2 g of CH₄ will react to produce = (45.2 × 36.04)/16.04 = 101.56 g of H₂O.
Thus, 101.56 of H₂O were obtained.
