Answer:
I = 18 x 10⁻⁹ A = 18 nA
Explanation:
The current is defined as the flow of charge per unit time. Therefore,
I = q/t
where,
I = Average Current passing through nerve cell
q = Total flow of charges through nerve cell
t = time period of flow of charges
Here, in our case:
I = ?
q = (9 pC)(1 x 10⁻¹² C/1 pC) = 9 x 10⁻¹² C
t = (0.5 ms)(1 x 10⁻³ s/1 ms) = 5 x 10⁻⁴ s
Therefore,
I = (9 x 10⁻¹² C)/(5 x 10⁻⁴ s)
<u>I = 18 x 10⁻⁹ A = 18 nA</u>
micrometer is used to measure the diameter of a thin wire
Answer:
B. The "Learner" was working with Milgram.
Explanation:
just took the test
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Answer:
W = 0J
Explanation:
The work done by the dresser is described as
W = f d (cos θ)
F has been given as the weight of this dresser. And it is 3500 N
d = 0 m
When you put these values into the equation
W = 3500 x 0 x cosθ
W = 0 J
This value tells us that the work done on this dresser is zero. No work has been done. Therefore the last option answers the question.
Answer: 38.2 μC
Explanation: In order to solve this problem we have to use the relationship for a two plate capacitor with a dielectric so:
C= Q/V= we also know that for two paralel plates C=εo*k*A/d and V=E/d
where k is the dielectric constant, A plate area, V is potential difference; E electric field and d the separation between the plates.
reorganizing we have:
Q/A=σ= E*k/εo= 1.2 * 10^6*3.6/8.85 * 10^-12=38.2μC
