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OLga [1]
3 years ago
5

What is comma please plz me.!!​

Physics
2 answers:
son4ous [18]3 years ago
7 0

Answer:

A comma.....

Explanation:

Looks like this (,), and can be used if you have run-on sentences.

I hope this helps :)

Sliva [168]3 years ago
7 0

hi

what's up

wrud

hmm

hmm

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Suppose you increase your walking speed from 7 m/s to 15 m/s in a period of 3 s. What is your acceleration?
lisov135 [29]

You asked the question twice I answered it on the last one

7 0
3 years ago
Ahmed fills a basket with shopping weighing 10 kg. How much work is being done on the shopping basket when he lifts it verticall
NISA [10]

The work done by the shopping basket is 147 J.

<h3>When is work said to be done?</h3>

Work is said to be done whenever a force moves an object through a certain distance.

The amount of work done on the shopping basket can be calculated using the formula below.

Formula:

  • W = mgh

Where:

  • W = Amount of work done by the basket
  • m = mass of the shopping basket
  • h = height of the shopping basket
  • g = acceleration due to gravity.

Form the question,

Given:

  • m = 10 kg
  • h = 1.5 m
  • g = 9.8 m/s²

Substitute these values into equation 2

  • W = 10(1.5)(9.8)
  • W = 147 J.

Hence, The work done by the shopping basket is 147 J.

Learn more about work done here: brainly.com/question/18762601

6 0
2 years ago
Whats the answer to 10a² - 6ab + 10 -2a² - 4ab +15b?​
Angelina_Jolie [31]
8a2-10ab+15b+10 Explaintion:

8 0
3 years ago
Whats the answer to 45 + 54 ÷ p - q
Lynna [10]
There’s nothing to answer to
4 0
3 years ago
We wrap a light, nonstretching cable around a 8.00 kg solid cylinder with diameter of 30.0 cm. The cylinder rotates with negligi
antoniya [11.8K]

Answer:

h = 16.67m

Explanation:

If the kinetic energy of the cylinder is 510J:

Kc=510=1/2*Ic*\omega c^2

\omega c=\sqrt{510*2/Ic}

Where the inertia is given by:

Ic=1/2*m_c*R_c^2=1/2*(8)*(0.15)^2=0.0225kg.m^2

Replacing this value:

\omega c=106.46rad/s

Speed of the block will therefore be:

V_b=\omega_c*R_c=106.46*0.15=15.969m/s

By conservation of energy:

Eo = Ef

Eo = 0

Ef = 510+1/2*m_b*V_b^2-m_b*g*h

So,

0 = 510+1/2*m_b*V_b^2-m_b*g*h

Solving for h we get:

h=16.67m

3 0
3 years ago
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