Answer:
3.467 s
Explanation:
given,
distance , d = 49 mm = 0.049 m
initial speed of the of the rock, v = 17 m/s
time taken by the Heather rock to reach water
using equation of motion
taking downward as negative
4.9 t² + 17 t - 0.049 = 0
now,
t₁ = -3.47 s , 0.0028 s
rejecting negative values
t₁ = 0.0028 s
now, time taken by the ball of Jerry
using equation of motion
taking downward as negative
4.9 t² - 17 t - 0.049 = 0
now,
t₂ = 3.47 s ,-0.0028 s
rejecting negative values
t₂ = 3.47 s
now, time elapsed is = t₂ - t₁ = 3.47 - 0.0028 = 3.467 s
<span>Let q1 = -10.0 nC , and q2 = 20.0 nC
E1(P) + E2(P) = 0
|E1| = |E2|
|q1|/r1^2 = q2/r2^2
r2/r1 = sqr(q2/|q1|) = sqr 2
r2 = r1 + d
Solving : r1 = d/(sqr2 -1) = 33.8 cm ; r2 = 47.8 cm
(a) V = (1/4pi €o)(q2/r2 + q1/r1) = 110 V
(b) V=0 |q1|/r1 = q2/r2
r2 = 2 r1 ; r2 + r1 = d
solving
r2 = 28/3 cm ; r1 = 14/3 cm
E = E1 + E2 = (1/4pi€o)(|q1|/r1^2 + q2/r2^2)
E is // at X axis and direct from q2 to q1.</span>
Answer:
e) True. Measure the own values, so everything seems normal
Explanation:
In the case of special relativity, it is explicitly stated that the speed of light is constant and equal to c for all inertial observers. For this reason the measures of time and length are no longer the same for observers moving with respect to each other.
We call the time and the proper length the magnitude measured for an observer who does not move with respect to the measurement system.
In this case the astronomer is on the ship, for him he does not feel the movement of it, they are at rest with respect to each other. Therefore, their measurements are the so-called ones, this means that their values do not change since the two go at the same speed.
In examining the final statements we have
A) False. The mass measures not
B) False. Measure own length
C) False
D) false
e) True. Measure the own values, so everything seems normal
