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VashaNatasha [74]
1 year ago
10

A 12 kg block is accelerating at the rate of 9.0 m/s? while being acted on by two forces.

Physics
1 answer:
Aliun [14]1 year ago
8 0

Answer:

See below

Explanation:

F = ma

F = 12 * 9 = 108 N

  108 N  needed      <u> add  30 N more east </u>

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It’s C
Cause Impulse is found by multiplying the force and change in time (which is simply time)
So if you rearrange the equation for time you end up dividing Impulse by force.
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Read 2 more answers
Consider a box weight 2700 newtons resting on the ground. If the area of the box touching the ground is 1.5 square meters, what
Neko [114]

Answer:

The answer to your question is 1800 Pa

Explanation:

Data

Weight = 2700 N

Area = 1.5 m²

Pressure = ?

Formula

Pressure = Force / Area

The Pressure is defined as the force exerted per unit area.

-Substitution

 Pressure = 2700 / 1.5

-Result

 Pressure = 1800 Pa

The units of pressure are Pascals (Pa)

6 0
2 years ago
Additional Problem: A simple pendulum, consisting of a string (of negligible mass) of length L with a small mass m at the end, i
kykrilka [37]

Answer:

a)   v = √ 2gL  abd  b)  θ = 45º

Explanation:

a) for this part we use the law of conservation of energy,

Highest starting point

       Em₀ = U = mg h

Final point. Lower

       Em₂ = ½ m v²

      Em₀ = Em₂

      m g h = ½ m v²

      v = √2g h

      v = √ 2gL

b) the definition of power is the relationship between work and time, but work is the product of force by displacement

     P = W / t = F. d ​​/ t = F. v

If we use Newton's second law, with one axis of the tangential reference system to the trajectory and the other perpendicular, in the direction of the rope, the only force we have to break down is the weight

     sin θ = Wt / W

     Wt = W sin θ

This force is parallel to the movement and also to the speed, whereby the scalar product is reduced to the ordinary product

     P = F v

The equation that describes the pendulum's motion is

    θ = θ₀ cos (wt)

Let's replace

    P = (W sin θ) θ₀ cos (wt)

    P = W θ₀ sint θ cos (wt)

We use the equation of rotational kinematics

    θ = wt

    P = Wθ₀ sin θ cos θ

Let's use

   sin 2θ = 2 sin θ cos θ

   P = Wθ₀/2 sin 2θ

This expression is maximum when the sine has a value of one (sin 2θ = 1), which occurs for 90º,

    2θ = 90

    θ = 45º

5 0
3 years ago
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