This homework is due tomorrow

I need some help with graphing again.

Rashid [163]

To find the x intercepts, we need to put the standard form equation into factored form.

Which two numbers multiply to -8 and add to -2?

$-4*2=-8$

$-4+2=-2$

So the factored form is

$(x-4)(x+2)$

That means the x intercepts are at $x=4,-2$

So now we have the x intercepts.

To find the vertex, we need to convert the standard form equation into vertex form.

The formula of vertex form is $y=a(x-h)^2+k$

Since the a value in the standard form equation is 1, the a value in vertex form is also one.

The h value can be found using the formula $h=\frac{-b}{2a}$

Which comes out to $\frac{2}{2}$ or 1.

To find the k value, we can just plug in what we got for h back into the equation.

$(1)^2-2(1)-8=-9$

So the vertex is $(1,-9)$ .

This also means the axis of symmetry is $x=-1$

Finally, to find the y intercept, we plug in 0 for x and solve.

$(0)^2-2(0)-8=-8$

So the y intercept is $(0,-8)$ .

8 0

3 years ago

What is the range of the data set? {43.2, 46.8, 44.5, 46.8, 44.2, 41.9, 45.8, 46.9, 41.2, 46.8, 44.1}

lilavasa [31]

Answer:

the range of this answer is 5.6

3 0

3 years ago

alexandr1967 [171]

Answer:

Traingle LKJ is similar to triangle LMK is similar to triangle KMJ

Step-by-step explanation:

6 0

2 years ago

Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work

Alona [7]

Answer:

$1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x$

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

Step-by-step explanation:

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x for 0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

= 18x - 144 + 96

= 18x - 48 for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

$f(x)=\bigg\{\begin{array}{ll}12x&0\leq x$

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D: 0 ≤ x ≤ 24 → D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

= 0

The maximum hours he can work in one day is 24 (although unlikely, it is theoretically possible).

f(x) = 18x - 48

f(24) = 18(24) - 48

= 432 - 48

= 384

D: 0 ≤ y ≤ 384 → D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

4 0

3 years ago

Find the cotangent of angle B. 1. 12/5 2. 12/13 3. 13/12 4. 5/12

labwork [276]

Cot = Cos/Sin

Cos = 12/13
Sin = 5/13

Therefore, 12/3 divided by 5/13 equals 12/5

Answer is 1.

3 0

3 years ago

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