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dezoksy [38]
2 years ago
15

Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between bakin

g soda and citric acid below.
C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3H2O + 3CO2

How many milliliters of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda?

** I NEED HELP ASAP
Chemistry
1 answer:
Gwar [14]2 years ago
5 0

The molarity of the solution is the moles dissolved per liter. The volume of 0.8 M citric acid solution will be 74.16 mL.

<h3>What is molarity?</h3>

Molarity of the solution is the concentration that is given by the moles of the solute that are dissolved to make the solution in liters.

The chemical reaction between baking soda and citric acid is shown as:

C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Given,

Molarity = 0.8 M

Mass of baking soda = 15 grams

The molar mass of baking soda = 84.007 g/mol

Moles of baking soda = 15 ÷ 84.007 = 0.178 moles

From the reaction, it can be said that 3 moles of baking soda are required to react with 1 mole of citric acid. So, 0.178 moles will need, 0.059 moles.

The volume of citric caid needed is calculated as:

M = moles ÷ volume

Volume (L) = 0.059 ÷ 0.8

= 0.07416 L

Volume is converted into mL as:

1 L = 1000 mL

0.07416 L = 74.16 mL

Therefore, 74.16 mL is the volume of citric acid needed.

Learn more about molarity here:

brainly.com/question/7145257

#SPJ1

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