is there a table or something you can add because I cant tell anything with the information you gave.
<span>It is easier to multiply. For example: 63 multiply by 7
</span><span>63 x 7 = (60+3) x 7 = 60 x 7 + 3 x 7 = 420 + 21 = 441
</span>
Another example : <span>25 x 73
</span>25 x 73 = (20+5) x (70+3) = 20 x 70 + 20x3 + 5x70 + 5x3
= 1400 + 60 + 350 + 15 = 1875
Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have
We know that,
Subtract both sides by 25.
We need to find the number of people who have a school certificate only, i.e. 
.
Therefore, 9 people have a school certificate only.
Let's make a system of equations to solve for this:
n + q = 84
0.05n + 0.25q = 12.80
where n = nickels and q = quarters.
---
Solve for n in the first equation by subtracting q from both sides.
n = 84 - q
---
Plug n into the second equation.
0.05(84 - q) + 0.25q = 12.80
Distribute 0.05 inside the parentheses.
4.2 - 0.05q + 0.25q = 12.80
Combine like terms.
4.2 + 0.2q = 12.80
Subtract 4.2 from both sides.
0.2q = 8.6
Divide both sides by 0.2.
q = 43
---
Plug 43 for q in the first equation.
n + (43) = 84
Subtract 43 from both sides.
n = 41
---
There are 41 nickels and 43 quarters in the piggy bank. ✅
Answer:
We just have to multiply not cross multiply,
10/18
Now, divide the equation
5/9 will be ur answer
