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Zina [86]
3 years ago
11

Please help me!! i am struggling on these

Mathematics
1 answer:
Greeley [361]3 years ago
6 0

Answer:

The input units are missing

The output units are missing

Step-by-step explanation:

The input units are missing

The output units are missing

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I'm abt to burn my house down follow my insta, rsokolskiy9, for the full video
ELEN [110]

Answer:

oh my

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Review your answers to Question 2. What happens to the coordinates of a shape when the shape reflects about the x-axis? What hap
mixas84 [53]

Answer:

When the shape reflects about the x-axis, the x-coordinate remains unchanged but the y-coordinate becomes negative. When the shape reflects about the y-axis, the y-coordinate remains the same but the x-coordinate becomes negative.

Step-by-step explanation:

Sample answer from Edmentum

4 0
3 years ago
How does the graph of the function g(x) = 2x – 4 differ from the graph of f(x) = 2x
Lena [83]

9514 1404 393

Answer:

  the y-intercepts differ

Step-by-step explanation:

The x-coefficient is the same for each function, so parallel lines are described. The function g(x) has a y-intercept of -4; f(x) has a y-intercept of 0.

The graphs differ in their intercepts.

__

<em>Additional comment</em>

g(x) can be considered to be a translation downward of f(x) by 4 units. The same graph of g(x) can be obtained by translating f(x) to the right by 2 units. That is, both the x-intercepts and y-intercepts differ between the two functions.

5 0
3 years ago
Please solve. NO EXPLAINATION NEEDED. I NEED ANSWER FAST
nexus9112 [7]

Answer:

11 and 22

Step-by-step explanation:

We can say that BC=2AC.

Since AB=33, AC=11 and BC=22.

4 0
2 years ago
A random sample of n observations is selected from a normal population to test the null hypothesis that muμequals=10. Specify th
brilliants [131]

Answer:

Step-by-step explanation:

a) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 13

Since α = 0.01, the critical value is determined from the t distribution table. Recall that this is a two tailed test. Therefore, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

The critical value is 3.012

The rejection region is area > 3.012

b) Ha: μ > 10

This is a right tailed test

n = 23

α = 0.1

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.319

The rejection region is area > 1.319

c) Ha: μ > 10

This is a right tailed test

n = 99

α = 0.05

We would reject the null hypothesis if the test statistic is greater than the table value of 1 - α

1 - α = 1 - 0.05 = 0.95

The critical value is 1.66

The rejection region is area > 1.66

d) Ha: μ < 10

This is a left tailed test

n = 11

α = 0.1

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.1 = 0.9

The critical value is 1.363

The rejection region is area < 1.363

e) H0: μ = 10

Ha: μ ≠ 10

This is a two tailed test

n = 20

Since α = 0.05, we would find the critical value corresponding to 1 - α/2 and reject the null hypothesis if the absolute value of the test statistic is greater than the value of t 1 - α/2 from the table.

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

The critical value is 2.086

The rejection region is area > 2.086

f) Ha: μ < 10

This is a left tailed test

n = 77

α = 0.01

We would reject the null hypothesis if the test statistic is lesser than the table value of 1 - α

1 - α = 1 - 0.01 = 0.99

The critical value is 2.376

The rejection region is area < 2.376

7 0
3 years ago
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