If my birthday was around that time I would be twenty eight years old. 1989-2017 gives me twenty eight
I think it would be 8 miles: it would have been 2 hours, so 4 * 2 is 8 miles.
:) Hope this helps!
Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa 2 =b 2+2 + c 2
−2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab 2=
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n} ba =nm
\ l^2 = ab - mnl 2=ab-mm
A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
\iits whatever A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=
4R
abc
- R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=
p(p−a)(p−b)(p−c)
-84 is a real number, a rational number, and an integer
Answer:
7.5 MW
Step-by-step explanation:
The power generated from a falling water is a function of its height and volume. The power generated an be calculated using the formula:
Power (P) = Density(ρ) * volume flow rate(Q) * acceleration due to gravity(g) * height(h)
P = ρQgh
But Qh = Velocity(v) * volume(V).
Hence power = ρvgV
Given that ρ of water = 1000 kg/m³, v = 75 m/s, V = 10 m³, g = 10 m/s². Substituting:
P = ρvgV = 1000 * 75 * 10 * 10 = 7500000 W
P = 7.5 MW
