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tatiyna
3 years ago
13

Suppose a system of two particles, represented by circles, have the possibility of occupying energy states with 0, 10, or 20 J.

Collectively, the particles must have 20 J of total energy. Are there any other energetically equivalent configurations?
Chemistry
1 answer:
MrMuchimi3 years ago
4 0

Answer:

Explanation:

The possible energy states for the particles are 0, 10 and 20 J.  

The constraint in the system is that the total energy of the particles must be 20 J.

One given configuration where the total energy is 20 J is if both the particles occupy the 10 J state.

Hence, (10;10) is the given configuration.

Another possibility is if one of the particle is in 0 J state and another is in 20 J state. Hence, the system has a total energy of 0+20 = 20 J.

Hence, the possible configuration can be written as (0;20) or (20;0) which are energetically equivalent to the given configuration. Note that if the circles are indistinguishable, then the configuration (0,20) and (20,0) is the same thing.

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Which of the following molecules can be used in catabolic reactions to generate the carbon backbones required for gluconeogenesi
sleet_krkn [62]

Answer:

The correct option is A

Explanation:

Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.

<u>All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis</u>. Thus, the correct option is a.

3 0
3 years ago
Please help on this one?
Bezzdna [24]

Answer:

\text{C. } _{36}^{85}\text{Kr}

Explanation:

Your nuclear equation is  

_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} +\, _{x}^{y}\text{X}

The main point to remember in balancing nuclear equations is that

  • the sum of the superscripts and must be the same on each side of the equation.
  • the sum of the subscripts must be the same on each side of the equation.  

Then  

85 = 0 + y, so y = 85 - 0 = 0  

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.  

The nuclear equation becomes  

_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} + \, _{36}^{85}\text{Kr}

4 0
3 years ago
Read 2 more answers
The sink-float method is often used to identify the type of glass material found at crime scenes by determining its density.
Olegator [25]

Answer:

<em><u>Glass that will sink</u></em>

  • alkali zinc borosilicate with a density of 2.57 g/mL in a solution with a density of 2.46 g/mL

  • potash soda lead with a density of 3.05 g/mL in a solution with a density of 1.65 g/mL

<em><u>Glass that will float</u></em>

  • soda borosilicate with a density of 2.27 g/mL in a solution with a density of 2.62 g/mL

  • alkali strontium with a density of 2.26 g/mL in a solution with a density of 2.34 g/mL

<em><u>Glass that will not sink or float</u></em>

  • potash borosilicate with a density of 2.16 g/mL in a solution with a density of 2.16 g/mL

Explanation:

Density is the property of matter that states the ratio of the amount of matter, its mass, to the space occupied by it, its volume.

So, the mathematical expression for the density is:

  • density = mass / volume

By comparing the density of a material with the density of a liquid, you will be able to determine whether object will float, sink, or do neither when immersed in the liquid.

The greater the density of an object the more it will try to sink in the liquid.

As you must have experienced many times an inflatable ball (whose density is very low) will float in water, but a stone (whose denisty is greater) will sink in water.

The flotation condition may be summarized by:

  • When the density of the object < density of the liquid, the object will float
  • When the density of the object = density of the liquid: the object will neither float nor sink
  • When the density of the object > density of the liquid: the object will sink.

<em><u>Glass that will sink</u></em>

  • alkali zinc borosilicate with a density of 2.57 g/mL in a solution with a density of 2.46 g/mL, because 2.57 > 2.46.

  • potash soda lead with a density of 3.05 g/mL in a solution with a density of 1.65 g/mL, because 3.05 > 1.65.

<u><em>Glass that will float</em></u>

  • soda borosilicate with a density of 2.27 g/mL in a solution with a density of 2.62 g/mL, because 2.27 < 2.62.

  • alkali strontium with a density of 2.26 g/mL in a solution with a density of 2.34 g/mL, because 2.26 < 2.34.

<em><u>Glass that will not sink or float</u></em>

  • potash borosilicate with a density of 2.16 g/mL in a solution with a density of 2.16 g/mL, because 2.16 = 2.16
8 0
4 years ago
: If you know that a ∝ b and a ∝ c, then you can also say that a ∝ bc, or the product of b and c. Take the above three proportio
aleksley [76]

Answer:

V ∝ abc

Explanation:

This task is a joint variation task involving only direct proportionality:

Direct variation is one in which two variables are in direct proportionality to each other. This means that as one increases, the other variable also increases and vice - versa.

Joint variation is one in which one variable is dependent on two or more variables and varies directly as each of them.

In this exercise:

If a ∝ b and a ∝ c, then a ∝ bc

Taking the above three proportionalities,

V ∝ a ∝ b ∝ c

V ∝ a ∝ bc

V ∝ abc

3 0
3 years ago
How many energy levels are partially or fully occupied in a neutral atom of calcium?
mina [271]
18 I think. <span>Essentially because there are so many more orbitals used by the molecules placed in the series. You will see that group 1-8 molecules always have a number of valence electrons equal to the group number. This reflects s and p orbital useage. Once d and f orbitals begin to be needed, the atoms become much more complex.</span>
6 0
4 years ago
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