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tatiyna
3 years ago
13

Suppose a system of two particles, represented by circles, have the possibility of occupying energy states with 0, 10, or 20 J.

Collectively, the particles must have 20 J of total energy. Are there any other energetically equivalent configurations?
Chemistry
1 answer:
MrMuchimi3 years ago
4 0

Answer:

Explanation:

The possible energy states for the particles are 0, 10 and 20 J.  

The constraint in the system is that the total energy of the particles must be 20 J.

One given configuration where the total energy is 20 J is if both the particles occupy the 10 J state.

Hence, (10;10) is the given configuration.

Another possibility is if one of the particle is in 0 J state and another is in 20 J state. Hence, the system has a total energy of 0+20 = 20 J.

Hence, the possible configuration can be written as (0;20) or (20;0) which are energetically equivalent to the given configuration. Note that if the circles are indistinguishable, then the configuration (0,20) and (20,0) is the same thing.

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the fraction of mass of liquid at 25°C.

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A

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The reactants would appear at a higher energy state than the products.

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What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme
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To calculate the wavelength of light, we use Rydberg's Equation:

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Putting the values in above equation, we get:

\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m

Converting this into nanometers, we use the conversion factor:

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3 years ago
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