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andrew-mc [135]
3 years ago
10

Phosphorous +Dilute hydrochloric acid

Chemistry
1 answer:
butalik [34]3 years ago
6 0

Phosphorus trichloride is the precursor to organophosphorus compounds that contain one or more P(III) atoms, most notably phosphites and phosphonates. ... PCl3 reacts vigorously with water to form phosphorous acid, H3PO3 and HCl: PCl3 + 3 H2O → H3PO3 + 3 HCl.
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(04.01 LC)
Marysya12 [62]

Answer:

Substance at the beginning of a reaction- reactant

Substance at the end of a reaction- product

Number placed before a compound in a chemical equation- stoichiometric coefficient

Explanation:

In a reaction equation, the species written on the left hand side of the equation are called the reactants.

The reactants combine to form the species on the right hand side of the reaction equation called products.

The stoichiometric coefficient is a number written before the formula of a compound in the reaction equation.

5 0
3 years ago
Which of the following elements is commonly found in the Earth's crust, living matter, oceans, and atmosphere? hydrogen , neon g
Svetlanka [38]

Answer: hydrogen

Explanation: hydrogen gas is a major component of water which occupies a large portion of the Earth's atmosphere

4 0
3 years ago
| A solution containing 4.48 ppm KMnO4 exhibits
Artist 52 [7]

Answer:

Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹

Explanation:

First convert Concentration from ppm inM or mol/l

⇒ Molar mass of KMnO₄ = 158.03 g

⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l

⇒ Molarity = \frac{4.48 X10^{-3} }{158.03X 1(lit)} = 2.83 x 10⁻⁵ molar

Absorbance (A) = - log(T)     ( T = % transmittance)

                          = - log(0.859)

                          = 0.06

According to Lambert Beer's law

     

                 ε = \frac{A}{C X l}

      or,      ε = \frac{0.06}{2.83 X 10^{-5}X1 cm }

      or,      ε = 2120.14 cm⁻¹M⁻¹

Where

    ε = Molar absorptivity

    A = absorbance

    C = Molar concentration of KMnO₄ solution

     l = length  

6 0
3 years ago
Suggest two ways to liquefy the gases.
aleksandr82 [10.1K]
There are two ways to liquefy a gas:

-- Increase the pressure on it.

-- Lower its temperature.

The liquefication is faster and easier if you do both.
3 0
3 years ago
A 13 Ohm resistor, R, is connected to a battery with unknown voltage, V, as shown below. The total current, I, flowing through t
wlad13 [49]

Answer:

16.12 V

Explanation:

Ohms law explains or portrays the relationship between the voltage (V), current (I) and resistance (R). This is represented using the equation as follows:

V = IR

Where;

V = voltage (Volts)

I = current (amperes)

R = resistance (ohms)

According to the information provided in the question, resistance (R) = 13 Ohm, current (I) = 1.24 Amperes, V = ?

V = 13 × 1.24

V = 16.12 V

3 0
2 years ago
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