All categories

3 years ago

10 POINTS

Chemistry

1 answer:

lorasvet [3.4K]3 years ago

5 0

De Broglie predicted that in his equation. The ball is not a particle.

You might be interested in

A LA TEMPERATURA DE 35°C, UNA MUESTRA DE DIOXIDO DE CARBONO OCUPA UN VOLUMEN DE 350 ML. ¿Qué CAMBIO DE VOLUMEN SE PRODUCIRA SI L

Kisachek [45]

Answer:

New volume = 150 mL

Explanation:

Initial temperature, T₁ = 35°C

Initial volume, V₁ = 350 mL

We need to find the change in volume when the temperature drops to 15°C.

The relation between the temperature and the volume is given by Charle's law. Let new volume is V₂. It can be given by :

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{350\times 15}{35}\\\\V_2=150\ mL$

So, the new volume is 150 mL.

8 0

3 years ago

What is the concentration of silver ions where silver iodide, Agl, is in a solution of hydroiodic

jonny [76]

Answer:

$[Ag^+]=2.82x10^{-4}M$

Explanation:

Hello there!

In this case, for the ionization of silver iodide we have:

$AgI(s)\rightleftharpoons Ag^+(aq)+I^-(aq)\\\\Ksp=[Ag^+][I^-]$

Now, since we have the effect of iodide ions from the HI, it is possible to compute that concentration as that of the hydrogen ions equals that of the iodide ones:

$[I^-]=[H^+]=10^{-3.55}=2.82x10^{-4}M$

Now, we can set up the equilibrium expression as shown below:

$Ksp=8.51x10^{-17}=(x)(x+2.82x10^{-4})$

Thus, by solving for x which stands for the concentration of both silver and iodide ions at equilibrium, we have:

$x=[Ag^+]=2.82x10^{-4}M$

Best regards!

6 0

3 years ago

I’ll give the brainliest

Readme [11.4K]

Answer:

Water gradually degrades them until the metal parts rust and the other materials deteriorate.

Explanation:

8 0

3 years ago

In the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl, if 6 moles of fecl2 are added to 6 moles of naoh, how many moles of fecl2 woul

pychu [463]

The balanced chemical reaction would be

fecl2 + 2naoh = fe(oh)2(s) + 2nacl

Initial amounts of the reactants are given, so, we need to determine which of the reactants is the limiting reactant and use this amount to determine what is asked. However, what is being asked is how many of the FeCl2 is used in the reaction, showing that it is NaOH that is the limiting reactants. Thus, we just use the initial amount of NaOH and relate the substances by the chemical reaction as follows:

6 mol NaOH ( 1 mol FeCl2 / 2 mol NaOH ) = 3 mol FeCl2

Therefore, 3 moles of FeCl2 is used up and 3 moles of FeCl2 is also left after the reaction.

5 0

3 years ago

Read 2 more answers

Part A Which acid in each of the following pairs has the stronger conjugate base? Match the words in the left column to the appr

vichka [17]

Answer:

H₂S

H₂CO₃

NH₄⁺

Explanation:

Which acid in each of the following pairs has the stronger conjugate base?

According to Bronsted-Lowry acid-base theory, the weaker an acid, the stronger its conjugate acid. Especially for weak acids, pKa gives information about the strength of such acid. The higher the pKa, the weaker the acid.

Of the acids HCl or HF, the one with the stronger conjugate base is HF because it is a weak acid.

Of the acids H₂S or HNO₂, the one with the stronger conjugate base is H₂S because it is a weaker acid. pKa (H₂S) = 7.04 > pKa (HNO₂) = 3.39

Of the acids H₂CO₃ or HClO₄, the one with the stronger conjugate base is H₂CO₃ because it is a weak acid.

Of the acids HF or NH₄⁺, the one with the stronger conjugate base is NH₄⁺ because it is a weaker acid. pKa (HF) = 3.17 < pKa (NH₄⁺) = 9.25

6 0

3 years ago