Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
![\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B101.3%7D%7BP_1%7D%29%3D%5Cfrac%7B41100%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298K%7D-%5Cfrac%7B1%7D%7B373K%7D%5D)
Therefore, the vapor pressure of water at 298 K is 3.565kPa.
The trend will be such that the time taken for the cross to disappear will be increasing.
<h3>Rate of reactions</h3>
The rate of reactions is affected by the concentration of reactants. The more concentrated the reactants are, the more the rate of the reaction, and vice versa. This is based on the condition that all other factors are kept constant.
In the illustrated reaction, the volume of sodium thiosulfate decreases downward while the volume of water increases. This means that the sodium thiosulfate gets more diluted as we move downward.
Thus, the reaction rate will keep decreasing. In other words, more time would be needed for the cross to disappear as the concentration of sodium thiosulfate decreases.
More on concentration and rate of reactions can be found here: brainly.com/question/13764840
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Answer:
A normal atom has a neutral charge. When you are missing electrons it has a positive charge. When you have extra electron, you have a negative charge. I am not sure what the answer to your second question is, sorry.
Explanation:
Explanation:
it contains 6.02*1023atoms
