Well you are at a 86% so t<span>his is considered a "B" grade on an average grade scale. If you take 50 points we would need to know the Total point you could have got in that class to be able to see how much a percent was the assignment work and then take that percentage of the assignment and subtract it from the 86% to see where on the scale you would fall in after the assignment points were taken off. Hope this helps :)
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Answer:
<u>d) 1.8 atm</u>
Explanation:
<u>According to Boyle's Law,</u>
Here, we are given :
- <u>P₁ = 1.5 atm</u>
- <u>T₁ = 25°C = 298 K</u>
- <u>T₂ = 75°C = 348 K</u>
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<u>Solving</u>
- P₂ = P₁T₂/T₁
- P₂ = 1.5 x 348 / 298
- P₂ = 522/298
- P₂ = <u>1.8 atm</u> (approximately)
Explanation:
Yes, the equation is balanced. There are the same number of Hydrogen (H) and Oxygen (O) atoms on both sides of the equation.
Answer:
3-
Explanation:
Sodium aurothiosulfate is a salt with the formula Na₃Au(S₂O₃)₂. The cation of the salt is sodium ion, and the anion is aurothiosulfate ion. We can determine the charge of the aurothiosulfate ion, considering that the sum of the positive and negative charges must be equal to the charge of the compound, which is zero.
3 × Na⁺ + 1 × Au(S₂O₃)₂ⁿ⁻ = 0
3 × +1 + 1 × Au(S₂O₃)₂ⁿ⁻ = 0
Au(S₂O₃)₂ⁿ⁻ = 3-
I've seen a question just like this but the 9.50L was 10 and the 23.0L was 20.0 and the answer was 328mmhg idk if they could be different or something.