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Gre4nikov [31]
3 years ago
9

Which process occurs at the anode in an electrochemical cell?

Chemistry
1 answer:
prisoha [69]3 years ago
5 0
Oxidation occurs at the anode, so your answer is (2) loss of electrons
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A student carries out a chemical reaction that produces a brown powder. How should the student measure the amount of product for
adoni [48]
The mass of the solid product of the reaction is determined by weighing.
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3 years ago
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Is gastric (stomach) fluid an acid or a base?
Vitek1552 [10]

Answer: the such thing that we call gastric acid, is made/produced by the cells that srebwithi any lining of our stomac, they are coupled in places like feedback system that extend to the acid production when it is needed.

other cells that are within our stomach will bicarbonat, at the base to buffer the fluid making sure that it doesn’t become too acidic

so yes it is

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3 0
3 years ago
What is the particle that is labeled with a question mark (?) in the diagram?
Nat2105 [25]

Answer is: quark.

Quark is a type of elementary particle and a fundamental constituent of matter.

Quarks form composite hadrons (protons and neutrons). Protons and neutrons are in the nucleus of an atom.

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There are six types of quarks: up, down, strange, charm, bottom, and top.

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3 years ago
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You perform a distillation to separate a mixture of propylbenzene and cyclohexane, and you obtain 2.9949 grams of cyclohexane (d
Romashka-Z-Leto [24]

Answer:

66.67%

Explanation:

From the given information:

mass of cyclohexane = 2.9949 grams

density of cyclohexane = 0.779 g/mL

Recall that:

Density = mass/volume

∴

Volume = mass/density

So, the volume of cyclohexane = 2.9949 g/ 0.779 g/mL

= 3.8445 mL

Also,

mass of propylbenzene = 1.6575 grams

density of propylbenzene = 0.862 g/mL

Volume of propylbenzene =  1.6575 g/ 0.862 g/mL

= 1.9229 mL

The volume % composition of cyclohexane from the mixture is:

= (\dfrac{v_{cyclohexane}}{v_{cyclohexane}+v_{propylbenzene}})\times 100

= (\dfrac{3.8445}{3.8445+1.9229})\times 100

= (\dfrac{3.8445}{5.7674})\times 100

= 66.67%

6 0
3 years ago
Explain in words or using your diagrams how beryllium atoms would react with fluorine atoms.
Marysya12 [62]

Explanation:

To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;

  Be  = 2, 2

  F  = 2, 7

 Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.

When Be loses two electrons it becomes isoelectronic with He;

                 Be →  Be²⁺ + 2e⁻  

Also, when fluorine gains  an electron, it becomes isoelectronic with Ne;

               F  + e⁻ →  F⁻

This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.

      Hence;

           Be²⁺  + 2F⁻ → BeF₂

8 0
2 years ago
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