It's 95 F
The formula is the following:
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Answer:
C10H22
Explanation:
Molecular Solids comprises of a Vander waal's force of attraction between the molecule. These forces are very weak when compared to ionic and covalent bond.
In Carbon, Carbon is not a molecule but an atom. One of it unique characteristics is that it forms bonds with other carbon atoms. This property is know as catenation. The bond between these carbon atoms is know as covalent bond.
Graphite is an allotrope of carbon. It exists as black , slippery, hexagonal crystals.The carbon atoms in graphite forms flat layers and are joined together by strong covalent bonds. Graphite can be used as lubricant in engines.
Gold (Au) is an element on the periodic table with atomic number 79 and a mass number 197. It exists as a metal. Most times Gold forms hydrogen bonds.
C10H22 is known as decane. It is the tenth compound formed in the series of alkane family( an organic unsaturated carbon chain family). Alkanes are aliphatic hydrocarbons. The forces of attraction between the alkane family are weak.In decane , their exists Vander waal's force which makes Decane C10H22 a Molecular Solid.
Answer:
Static Electricity.
Explanation:
Static electricity is defined as 'an electric charge that has built up on an insulated body, often due to friction.' <u> It is an outcome of the disparity among the positive, as well as, negative charges residing in a body</u> or object and causes the charge to build up on the surface of the body. The accumulation of electric charges on the objects like wool, hair, silk, plastic, etc. causes them to possess static electricity. These charges stay on the surface until it is discharged or released through a source. Thus, <u>'static electricity</u>' is the correct answer.
pH of the buffer solution is 1.76.
Chemical dissociation of formic acid in the water:
HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq)
The solution of formic acid and formate ions is a buffer.
[HCOO⁻] = 0.015 M; equilibrium concentration of formate ions
[HCOOH] + [HCOO⁻] = 1.45 M; sum of concentration of formic acid and formate
[HCOOH] = 1.45 M - 0.015 M
[HCOOH] = 1.435 M; equilibrium concentration of formic acid
pKa = -logKa
pKa = -log 1.8×10⁻⁴ M
pKa = 3.74
Henderson–Hasselbalch equation: pH = pKa + log(cs/ck)
pH = 3.74 + log (0.015 M/1.435 M)
pH = 3.74 - 1.98
pH = 1.76
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