Answer:While in Europe, if you drive 119 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage ...
In his pamphlet Common Sense, Thomas Paine urged American colonists to establish their own nation. The correct option among all the options that are given in the question is option "1". The pamphlet by Thomas Paine actually urged the colonists to denounce the British rule. He was of the opinion that it was not fair that an island would rule over a total continent.<span>He also wrote that being a part of Britain would
unnecessarily drag America into unwanted wars with European countries.</span>
The pressure of the gas = 40 atm
<h3>Further explanation</h3>
Given
200 ml container
P = 2 atm
final volume = 10 ml
Required
Final pressure
Solution
Boyle's Law
At a fixed temperature, the gas volume is inversely proportional to the pressure applied
Input the value :
P₂ = P₁V₁/V₂
P₂ = 2 x 200 / 10
P₂ = 40 atm
Answer:
1). 1 mole of Carbon burnt in air
C + O2 →CO2
1 mole of carbon produces 1 mole of CO2 which is 44g of CO2
2). 1 mole of carbon is burnt in 16g of dioxygen
32g of O2 = 44g of CO2
1g of O2 = 44/32
CO2 (Dioxygen is limiting reagent)
16g of O2 = 4/32 × 16 = 22g of CO2 in one mole
3) 2 moles of Carbon burnt in 16g of dioxygen
16g of dioxygen is available, and thus it can combine with 0.5 mol of carbon to give 22g of CO2
The standard temperature and pressure is 273 K and 1 atm. Since, pressure is not changed we can use Charle's law for the calculations.
<span>Charle's law says "at a constant pressure, the volume of a fixed amount
of gas is directly proportional to its absolute temperature".
V α T
Where V is the volume and T is the temperature
in Kelvin of the gas. We can use this for two situations as,
V</span>₁/T₁ = V₂/T₂<span>
</span>V₁ =
806 mL<span>
T</span>₁ =
26 ⁰C = 299 K
V₂ <span>=
? </span><span>
T</span>₂ =
273 K<span>
<span>
By applying the
formula,
</span></span>(806 mL / 299 K) = (V₂ / 273 K)
V₂ = 735. 91 mL
<span>
Hence, the answer is "a".</span>
