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3 years ago

What is the name of the global wind pattern that affects all the other winds? It can reach speeds of up to 900 miles per hour.

Chemistry

1 answer:

qwelly [4]3 years ago

8 0

Explanation:

trade winds hope this help if u need anything else comment please

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Anna007 [38]

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<h3>Hope this helps :)</h3>

6 0

3 years ago

Two gas-containers, A and B, are connected with a valve. The first container, A, has a volume of 135 mL, and the second containe

stiv31 [10]

Answer:

85.5 mmHg is the pressure of the gas sample when the valve is opened.

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas in container A = 165 mmHg

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas in container A= $135 mL$

$V_2$ = final volume of gas = 135 mL + 117 mL = 252 mL

$T_1$ = initial temperature of gas in container A = $22.5^oC=273+22.5=295.5 K$

$T_2$ = final temperature of gas = $12.7^oC=273+12.7=285.7K$

Now put all the given values in the above equation, we get:

$P_2=\frac{P_1V_1\times T_2}{T_1\times V_2}$

$=\frac{165 mmHg\times 135 mL\times 285.7 K}{295.5 K\times 252 mL}$

$P_2=85.5 mmHg$

85.5 mmHg is the pressure of the gas sample when the valve is opened.

8 0

4 years ago

When a radioactive atom emits an alpha particle, the original atom's atomic number decreases by four.

solniwko [45]

Ya it is true, alpha particle is actually helium atom with no electrons !
He2+ and it has mass of 4 u ....So that is correct !

5 0

4 years ago

Calculate the vapor pressure of spherical water droplets of radius (a) 17 nm and (b) 2.0 μm surrounded by water vapor at 298 K.

Montano1993 [528]

Explanation:

Relation between pressure of water and its droplet is as follows.

$ln (\frac{p}{p_{o}}) = \frac{2 \gamma M}{r \rho RT}$

where, p = pressure of droplet

$p_{o}$ = water pressure in given temperature

$\gamma$ = $7.99 \times 10^{-3}$

M = Molecular Weight in Kg/Mol (0.018 for water)

r = radius in meters

$\rho$ = density of water in $Kg/m^{3}$ (1000 $kg/m^{3}$ )

R = ideal gas constant (8.31)

T = temperature in Kelvin

(a) We will calculate the value of p as follows.

p = $e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}$

= $e^{\frac{2 \times 0.07199 \times 0.018}{1.7 \times 10^{-8} \times 1000 \times 8.31 \times 298 K} \times 25.2$

= 26.8 torr

(b) And, vapor pressure of spherical water droplets of radius 2.0 $\mu m$ or $2 \times 10^{-6} m$

p = $e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}$

= $e^{\frac{2 \times 0.07199 \times 0.018}{2 \times 10^{-6} \times 1000 \times 8.31 \times 298 K} \times 25.2$

= 25.2 torr

7 0

4 years ago

What number represents water becoming water vapor in this diagram

vredina [299]

the answer is <u>"A" 1</u>

3 0

3 years ago

Read 2 more answers