Molar mass is the mass of each element multiplied by subscript, then added together.
So, we’ll do
C = 12g x 12 = 144 g
H = 1g x 22 = 22 g
O = 16g x 11 = 176 g
The total of all of these is the molar mass: 342 g in a mol
The amount of mols of each element in each compound is likely equal to its subscripts.
C = 12 mols
H = 22 mols
O = 11 mols
For the atoms, you’ll multiply each one of the above by Avogadro’s number
Avogadro’s Number: 6.02 x 10^23 atoms/mol
Answer:
This question is incomplete because of the absence of the molecules been referred to in the question. However, the molecules been referred to in the question is in the attachment below
Explanation:
First of all, we have to define lewis acid and lewis base.
A lewis acid is a substance that has the capacity to accept a pair of electrons. For example, H⁺. While a lewis base is a substance that is capable of donating a pair of electrons (to a lewis acid). For example, OH⁻.
Going by the definitions above, we can deduce the type of substance the molecules in the question (attachment) are
a. BF₃ (boron trifluoride) is a lewis acid because the central atom (as suggested to be focused on in the question) which is <u>boron, has the capacity to accept a pair of electrons</u>.
b. The central atom (carbon) in the compound (2-methyl propane) <u>also has the capacity to accept a pair of electrons</u> since it is positively charged (is electron deficient). Hence, it is a lewis acid.
c. The functional group in this compound (trimethyl borate) is the ether. Ethers are generally lewis bases because the oxygen atom in an ether can donate a pair of electrons from it's lone pair. However, the <u>presence of boron which is central to the compound</u> shows it is also a lewis acid, although weak (majorly due to the presence of the ethers).
Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.
b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.
Explanation: The decomposition of carbon disulfide is given as:

at t=0 4.83g 0 0
at t=37 days 4.83 - x x x
here,
x = amount of
utilised in the reaction
This reaction follows first order kinetics so the rate law equation is:

where, k = rate constant
t = time
= Initial mass of reactant
A = Final mass of reactant
a) For this, the value of

t = 370 days = 3196800 sec
= 4.83
A = 4.83-x
Putting values in the above equation, we get

x = 2.85g
Amount of
remained after 37 days = 4.83 - x
= 1.97g
b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.
Amount of carbon monosulfide formed = 2.85g
Answer:
A) Q + XZ = X + QZ is a single displacement reaction.
B) Q + Z = QZ is a synthesis reaction
C) QT = Q + T is a decomposition reaction
D) QT + XZ = QZ + XT is double replacement reaction.
Explanation:
A) Q + XZ = X + QZ
This is a single displacement reaction because it is one in which one element is substituted for another one in a compound. In this case X is substituted for Q.
B) Q + Z = QZ
This is a synthesis reaction because Q and z combine to form a single product QZ.
C) QT = Q + T
This is a decomposition reaction because the compound QT breaks down to form 2 simpler substances Q and T.
D) QT + XZ = QZ + XT
Thus is a double replacement reaction because QT and XZ have exchanged cations to form new compounds QZ and XT
Answer:
2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.
Explanation:

Mass of fat = 2.4 kg = 2.4 × 1000 g = 2400 g
1 kg = 1000 g
Molar mass of fat = M
M = 57 × 12 g/mol + 110 × 1 g/mol+ 6 × 16 g/mol = 890 g/mol[/tex]
Moles of fat = 
According to reaction , 2 moles of fat gives 110 moles of water. Then 2.6966 moles of fat will give ;
of water
Mass of 148.31 moles of water ;
148.31 mol × 18 g/mol = 2,669.58 g
2,669.58 grams of water will be produced by metabolism of 2.4 kilogram of fat.