Answer:
50%
Explanation:
In this case, it is imperative to know each genotype >>
1. Genotypes for leg trait
- LL: normal legs
- Ll: deformed legs
- ll: very short legs
2. Genotypes for fur trait
- BB: black fur
- Bb: brown fur
- bb: white fur
According to the data above, the parental cross is as follow:
BBLl X bbLl
The possible gametes for each parental genotype are as follow:
Parental 1 >> 1/2 BL; 1/2 Bl
Parental 2 >>1/2 bL; 1/2 bl
Punnett square to calculate the possible genotypes of offspring:
bL - bl
BL 1/4 BbLL - 1/4 BbLl
Bl 1/4 BbLl - 1/4 Bbll
In consequence, the expected proportion of offspring with deformed legs and brown fur (genotype BbLl) is 1/2, i.e., 50%.
Blue is the correct answer to that question from my math
Someone who is blood type<span> B could have a </span>genotype<span> of either BB or BO. A </span>blood <span>test of either </span>type<span> AB or </span>type<span> O is more informative. Someone with </span>blood type<span> AB must have both the A and B alleles.</span>
Example Alloxan-Induced Diabetes Triggers the Development of Periodontal Disease in Rats.