All categories

1 year ago

What is the answer to this maths watch question? Look at screenshot attached. Thank you.

Mathematics

2 answers:

Ivahew [28]1 year ago

4 0

Answer+Step-by-step explanation:

14 - 9 = 5 then (14 - 5 = 9 and 14 + 5 = 19)

…………………………………………………………………

1+18=19

2+17=19

3+16=19

4+15=19

5+14=19

6+13=19

7+12=19 ⇒ 7 - 12 = -5

8+11=19

9+10=19

forsale [732]1 year ago

3 0

14-x=9

14=x+9

x=14-9

x=5

14+5=19

x+y=19

x-y=(-5)

Adding both equations,

We get,

x+y=19

x-y=(-5)

2x=14

x=7

x+y=19

7+y=19

y=12

You might be interested in

Your school football team has 10 scheduled games for the season. You want to attend at least 4 games. How many different combina

viva [34]

24 combinations i believe

8 0

2 years ago

Write an equation in slope-intercept form that represents the graphed function.

damaskus [11]

Answer: Y = 1/4x - 2
Slope intercept form is y = mx + b
M is slope, and b is y intercept

Solving slope:
change in y over change in x is slope
The change in y from (0,-2) and (4,-1) is up one over four.
This can be represented as 1/4

Solving y-intercept:
Y-intercept is when x = 0 or when the line touches the y axis
As you can see on the graph, the y intercept is (0,-2) or -2

Final:
Y = 1/4x - 2

8 0

2 years ago

Luke earned a grade of 88% on his multiple choice history final that had a total of

weqwewe [10]

Answer:

176

Step-by-step explanation:

88% = 88/100

88 × 2 = 176

176/200

4 0

2 years ago

Read 2 more answers

The sides of a quadrilateral are 3, 4, 5, and 6. Find the length of the shortest side of a similar quadrilateral whose area is 9

Georgia [21]

Answer:

9 units.

Step-by-step explanation:

Let us assume that length of smaller side is x.

We have been given that the sides of a quadrilateral are 3, 4, 5, and 6. We are asked to find the length of the shortest side of a similar quadrilateral whose area is 9 times as great.

We know that sides of similar figures are proportional. When the proportion of similar sides of two similar figures is $\frac{m}{n}$ , then the proportion of their area is $\frac{m^2}{n^2}$ .