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natta225 [31]
3 years ago
15

Which statement is true about the atom?

Physics
1 answer:
slavikrds [6]3 years ago
7 0

Answer:

Its d

atome contain

negative electrons,

positive protons and uncharged neutrons.

Explanation:

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two cars are travelling side by side down a straight road in opposite directions. both cars are travelling at a speed of 22 m/s.
Nimfa-mama [501]

Answer: 44m/s

Explanation:

Speed of Car A travelling left = 22m/s

Speed of Car B travelling right = 22m/s

Now recall that relative speed of objects moving in opposite directions is equal to the sum of each speed

Hence, Relative speed = (Speed of Car A + Speed of Car B)

= (22m/s + 22m/s)

= 44m/s

3 0
3 years ago
The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N. How far is
Vlad [161]

Mercury is 35.98 million miles from the Sun.

4 0
3 years ago
Read 2 more answers
A 1kg sphere rotates in a circular path of radius 0.2m from rest and it reaches an angular speed of 20rad/sec in 10 second calcu
Len [333]

Answer:

0.4 m/s²

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1 kg

Radius (r) = 0.2 m

Angular speed (w) = 20 rad/sec

Time (t) = 10 s

Tangential acceleration (aₜ) =?

Next, we shall determine the angular acceleration (a) of the sphere. This can be obtained as follow:

Angular speed (w) = 20 rad/sec

Time (t) = 10 s

Angular acceleration (a) =?

a = w/t

a = 20/10

a = 2 rad/s²

Finally, we shall determine the tangential acceleration (aₜ) of the sphere. This can be obtained as follow:

The tangential acceleration (aₜ) and the angular acceleration (a) are related according to the equation:

Tangential acceleration (aₜ) = Angular acceleration (a) × Radius (r)

aₜ = ar

With the above formula, we can obtain the tangential acceleration (aₜ) as follow:

Radius (r) = 0.2 m

Angular acceleration (a) = 2 rad/s²

Tangential acceleration (aₜ) =?

aₜ = ar

aₜ = 2 × 0.2

aₜ = 0.4 m/s²

Therefore, the tangential acceleration is 0.4 m/s²

6 0
3 years ago
Which one would it be ?
MA_775_DIABLO [31]

the answer to you question is D.

8 0
3 years ago
Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe
vodka [1.7K]
 We will use formula for the orbital velocity of Venus, which is v = 35.02 km/s. 
    An average distance to the Sun ( In kilometers ) is:
    R = 0.723 * 149,579,871 km= 108,150,260 km.
    Than we will calculate the orbital period ( T ).
    v = 2 π R / T
    T = 2 π R / v
    T = 2 * 3.14 * 108,150,260 km / 126,072 km/s
    T = 5389.75 s ≈ <span>224.5 days
    The orbital period of Venus is approximately 224.5 days.</span>
6 0
3 years ago
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