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myrzilka [38]
2 years ago
9

Methane (CH4) undergoes combustion. Which products form?

Chemistry
2 answers:
zlopas [31]2 years ago
7 0
Carbon dioxide and water is formed
Ksivusya [100]2 years ago
5 0

Answer:

carbon dioxide (CO2) and water (H2O).

Explanation:

When methane burns in the air it has a blue flame. In sufficient amounts of oxygen, methane burns to give off carbon dioxide (CO2) and water (H2O). When it undergoes combustion it produces a great amount of heat, which makes it very useful as a fuel source. Methane is a very effective greenhouse gas.

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A major component of gasoline is octane (C8H18). When liquid octane is burned in air it reacts with oxygen gas to produce carbon
Paraphin [41]

Answer:

The answer to your question is 0.4 moles of Oxygen

Explanation:

Data

Octane (C₈H₈)

Oxygen (O₂)

Carbon dioxide (CO₂)

Water (H₂O)

moles of water = ?

moles of Oxygen = 1

Balanced chemical reaction

                   C₈H₈  +10O₂  ⇒   8CO₂  +  4H₂O

              Reactant     Element     Products

                    8                 C                 8

                    8                 H                 8  

                   20                O               20  

Use proportions to solve this problem

                  10 moles of Oxygen ----------------- 4 moles of water

                    1 mol of Oxygen     ------------------ x

                    x = (4 x 1) / 10

                    x = 4 / 10

                    x = 0.4 moles of water

7 0
3 years ago
As stars get older, before they collapse, they throw off dust, heavy atoms and other materials an form a new
andre [41]

Answer:

B or D

Explanation:

.....I'm pretty sure I earned on some kids tv show

7 0
2 years ago
Read 2 more answers
Explain what is respiration in your own words..
nadezda [96]

Answer:

Plants using glucose to make ATP molecules during the process of photosynthesis which results in the plant releasing oxygen.

This is cellular respiration. ↑

8 0
2 years ago
9
Svetllana [295]

Answer:

0.0025moles

Explanation:

Molarity of a solution (M) = number of moles (n) ÷ volume (V)

According to this question, to make 250 mL of a 0.01 M solution of CaCl, the following number of moles is needed:

Volume = 250mL = 250/1000 = 0.250Litres.

Using; molarity = n/V

0.01 = n/0.250

n = 0.0025

n = 2.5 × 10^-3 moles.

5 0
2 years ago
A monoprotic weak acid, HA , dissociates in water according to the reaction HA(aq)↽−−⇀H+(aq)+A−(aq) The equilibrium concentratio
Pachacha [2.7K]

Answer:

pK_{a} of HA is 6.80

Explanation:

pK_{a}=-logK_{a}

Acid dissociation constant (K_{a}) of HA is represented as-

                K_{a}=\frac{[H^{+}][A^{-}]}{[HA]}

Where species inside third bracket represents equilibrium concentrations

Now, plug in all the given equilibrium concentration into above equation-

K_{a}=\frac{(2.00\times 10^{-4})\times (2.00\times 10^{-4})}{0.250}

So, K_{a}=1.6\times 10^{-7}

Hence pK_{a}=-log(1.6\times 10^{-7})=6.80

6 0
2 years ago
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