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myrzilka [38]
3 years ago
9

Methane (CH4) undergoes combustion. Which products form?

Chemistry
2 answers:
zlopas [31]3 years ago
7 0
Carbon dioxide and water is formed
Ksivusya [100]3 years ago
5 0

Answer:

carbon dioxide (CO2) and water (H2O).

Explanation:

When methane burns in the air it has a blue flame. In sufficient amounts of oxygen, methane burns to give off carbon dioxide (CO2) and water (H2O). When it undergoes combustion it produces a great amount of heat, which makes it very useful as a fuel source. Methane is a very effective greenhouse gas.

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What is the Molecular formula of a compound containing 63.53% Hydrogen, 8.24% Nitrogen, 28.23% Oxygen, and has a molecular mass
Sidana [21]
The molecular formula is H108NO3
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When 2.5 g of blue copper(ii) sulfate crystals were heated, 1.6 g of a white solid were left in tube A
Zinaida [17]

Answer:

b po answerpa brainlest

8 0
3 years ago
For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be prod
natima [27]

Answer:

(a)

Moles of ammonium chloride = 0.5 mole

Mass of ammonium chloride formed = 26.7455 g

(b)

Mole of CS_2 = 0.125 mole

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

Mole of H_2S = 0.25 mole

Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g

Explanation:

(a)

For the first reaction:-

NH_3_{(g)}+HCl_{(g)}\rightarrow NH_4Cl_{(s)}

The mole ratio of the reactants = 1 : 1

0.5 moles of ammonia react with 0.5 moles of hydrochloric gas to give 0.5 moles of ammonium chloride

So, <u>Moles of ammonium chloride formed = 0.5 moles</u>

Molar mass of ammonium chloride = 53.491 g/mol

<u>Mass = Moles * Molar mass = 0.5 * 53.491 g = 26.7455 g</u>

(b)

For the first reaction:-

CH_4_{(g)}+4S_{(s)}\rightarrow CS_2_{(l)}+2H_2S_{(g)}

The mole ratio of the reactants = 1 : 4

It means

0.5 moles of methane react with 2.0 moles of sulfur to give 0.5 moles of Carbon disulfide and 1.0 moles of hydrogen sulfide gas.

But available moles of S = 0.5 moles

Limiting reagent is the one which is present in small amount. Thus, S is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

4 moles of S produces 1 mole of CS_2

Thus,

0.5 moles of S produces \frac{1}{4}\times 0.5 mole of CS_2

<u>Mole of CS_2 = 0.125 mole</u>

Molar mass of CS_2 = 76.139 g/mol

<u>Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g</u>

4 moles of S produces 2 moles of H_2S

Thus,

0.5 moles of S produces \frac{2}{4}\times 0.5 mole of H_2S

<u>Mole of H_2S = 0.25 mole</u>

Molar mass of H_2S = 34.1 g/mol

<u>Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g</u>

<u></u>

7 0
3 years ago
What is the relative atomic mass of an element
Gennadij [26K]

Answer:

20.2 amu.

Explanation:

Let A represent isotope ²⁰X

Let B represent isotope ²²X

From the question given above, the following data were obtained:

For Isotope A (²⁰X):

Mass of A = 20

Abundance (A%) = 90%

For Isotope B (²²X):

Mass of B = 22

Abundance (A%) = 10%

Relative atomic mass (RAM) =?

The relative atomic mass (RAM) of the element can be obtained as follow:

RAM = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

RAM = [(20 × 90)/100] + [(22 × 10)/100]

RAM = 18 + 2.2

RAM = 20.2 amu

Thus, relative atomic mass (RAM) of the element is 20.2 amu

4 0
3 years ago
Which is a proper description of chemical equilibrium?
serg [7]
D) because both reactions are occurring at the same rate. They are not equal but their concentrations are constant.
3 0
3 years ago
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