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ludmilkaskok [199]
2 years ago
12

On a coordinate plane, a line is drawn from point j to point k. point j is at (negative 15, negative 5) and point k is at (25, 1

5). what are the x- and y- coordinates of point e, which partitions the directed line segment from j to k into a ratio of 1:4? x = (startfraction m over m n endfraction) (x 2 minus x 1) x 1 y = (startfraction m over m n endfraction) (y 2 minus y 1) y 1 (–13, –3) (–7, –1) (–5, 0) (17, 11)
Mathematics
1 answer:
Genrish500 [490]2 years ago
7 0

The required x- and y- coordinates of point e, which partitions the directed line segment is (17, 11)

<h3>Midpoint of coordinates</h3>

The middle point of two coordinates is known as its midpoint. The formula for calculating the midpoint of a coordinate is expressed as:

m(x,y)=(\frac{mx_1+nx_2}{m+n},  \frac{my_1+ny_2}{m+n})

Given the coordinate points J(-15, -5) and k(25, 15) partitioned in the ratio 1:4, the x- and y- coordinates of point e, which partitions the directed line segment is given as:

m(x,y)=(\frac{1(-15)+4(25)}{1+4},  \frac{1(-5)+4(15)}{1+4})\\m(x,y)=(\frac{85}{5}, \frac{55}{5} )\\m(x, y) = (17,11)

Hence the required x- and y- coordinates of point e, which partitions the directed line segment is (17, 11)

Learn more on midpoint here: brainly.com/question/5566419

#SPJ4

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Answer:

a

The null hypothesis is  H_o : \mu  =  13.4000

The alternative hypothesis is  H_a :  \mu \ne  13.4000

The null hypothesis is rejected

b

The  99% confidence level is   13.3930  < \mu  < 13.3994

Step-by-step explanation:

From the question we are told that

  The sample size is  n =  10

   The  population mean is  \mu =  13.4 000 \  angstroms

   The level of significance is  \alpha =  0.05

   The  sample data is  

13.3987, 13.3957, 13.3902, 13.4015, 13.4001, 13.3918, 13.3965, 13.3925, 13.3946, and 13.4002

Generally the sample mean is mathematically represented as

        \= x =  \frac{13.3987+ 13.3957\cdots +13.4002 }{10}

=>     \= x = 13.3962

Generally the sample standard deviation  is mathematically represented as

    \sigma = \sqrt{\frac{\sum (x_i - \= x)^2}{n} }

=> \sigma = \sqrt{\frac{ (13.3987 - 13.3962)^2 +  (13.3987 - 13.3962)^2 + \cdots + (13.3987 -13.4002)^2  }{10} }

=>  \sigma =0.0039

The null hypothesis is  H_o : \mu  =  13.4000

The alternative hypothesis is  H_a :  \mu \ne  13.4000

Generally the test statistics is mathematically represented as

      z  =  \frac{\= x - \mu}{\frac{\sigma}{\sqrt{n} } }

=>    z  =  \frac{13.3962 -  13.4000}{\frac{0.0039}{\sqrt{10} } }

=>   z =  3.08

Generally the p-value is mathematically represented as

       p-value  = 2P( z   >  3.08)

From the z-table  P(z >  3.08)= 0.001035

So

       p-value  = 2* 0.001035

      p-value  = 0.00207

So from the obtained value we see that

     p-value  < \alpha

Hence the null hypothesis is rejected

Consider the b question

Given that the confidence level is  99%  then the level of significance is

    \alpha =  (100 -99)\%

=> \alpha =  0.01

Generally from the normal distribution table critical value  of  \frac{\alpha }{2} is  

    Z_{\frac{\alpha }{2} } =  2.58

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>   E = 2.58  *  \frac{0.0039}{\sqrt{10} }

=>    E = 0.00318

Generally the 99% confidence interval is mathematically represented as

     13.3962   - 0.00318  < \mu  < 13.3962   +  0.00318

=>   13.3930  < \mu  < 13.3994

 

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Six hundred seven and four hundred nine one-thousandths. 
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