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3 years ago

1. (4x2 – 2x+8)+(x² + 3x - 2)

Mathematics

2 answers:

alexgriva [62]3 years ago

8 0

What you have to do is combine like terms.

This means combine 4x² with x²; -2x with 3x; 8 with -2

(4x² + x²) + (-2x + 3x) + (8 + (-2))

5x² + x + 6

Hope this helped!

~Just a girl in love with Shawn Mendes

krek1111 [17]3 years ago

4 0

Answer:

I simplify it and got 5x^2+z+6

Step-by-step explanation:

(4x2 – 2x+8)+(x² + 3x - 2)v=5x^2+z+6

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Margarita [4]

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3 years ago

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Given △XPS≅△DNF, find the values of x and y.

White raven [17]

Answer:

x = 3

y = 15

Step-by-step explanation:

If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:

XP ≅ DN

PS ≅ NF

XS ≅ DF

Given that:

XP = 4y - 3

DN = 57

NF = 51

XS = 17x + 3

DF = 54

Therefore:

XP = DN

4y - 3 = 57 (Substitution)

Add 3 to both sides

4y = 57 + 3

4y = 60

Divide both sides by 4

y = 60/4

y = 15

Also,

XS = DF

17x + 3 = 54 (substitution)

Subtract 3 from each side

17x = 54 - 3

17x = 51

Divide both sides by 17

x = 51/17

x = 3

4 0

2 years ago

What are the values of a, b and c in the quadratic equation -2x^2+4x-3=0?

AlladinOne [14]

Answer:

$a=-2\\b=4\\c=-3$

Step-by-step explanation:

In a quadratic equation in the Standard form

$ax^2+bx+c=0$

You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: $a\neq0$ ).

You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:

$-2x^2+4x-3=0$

Therefore, you can identify that the values of "a", "b" and "c" are the following:

$a=-2\\b=4\\c=-3$

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3 years ago

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il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

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3 years ago

List the factors of 24.

Sergio [31]

Answer:

Therefore , the factors of 24 are = 1,2,3,4,6,12 and 24

Step-by-step explanation:

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3 years ago

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