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2 years ago

What is the solution to this inequality?

Mathematics

1 answer:

Reika [66]2 years ago

3 0

<h3>Answer: Choice A) d > 5</h3>

Work Shown:

$-4(d-2) < -12\\\\-4d+8 < -12\\\\-4d < -12-8\\\\-4d < -20\\\\d > -20/(-4)\\\\d > 5$

In the second to last step, the inequality sign flips because we divided both sides by a negative number.

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Find the midpoint of A and B where A has coordinates (-7, 1)<br> and B has coordinates (3,-5).

zepelin [54]

Answer:

A (-7, 1) = (X1, Y1)

B (3, -5) = (X1, Y2)

Now,

Mid point = (X1 + X2÷2, Y1 + Y2 ÷ 2)

= {-7+3÷2, 1+(-5)÷2}

= (-4÷2, 1-5÷2)

= (-4÷2, -4÷2)

= (-2, -2)

Step-by-step explanation:

I hope it will help you to study.

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3 years ago

Estimate the different by rounding each number to the nearest tenth : 0.68-0.17

Amiraneli [1.4K]

Answer:

0.5

Step-by-step explanation:

0.68 - 0.17

0.68 ≈ 0.7

0.17 ≈ 0.2

0.7 - 0.2 = 0.5

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3 years ago

Evaluate 9!/6!3!<br><br> A: 1<br> B: 84<br> C: 68

Anika [276]

B, im hundred percent sure its right

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3 years ago

Mrs. Daly's reading classes were surveyed about their reading preferences. The data is summarized in the table below.

andriy [413]

Answer:

Required probability is 0.19

Step-by-step explanation:

The two-way table for the given data is,

Fiction Non-Fiction Total

9th grade 35 8 43

10th grade 52 12 64

Total 87 20 107

It is required to find the probability of the students who prefer to read non-fiction novels, given that they are in 9th grade.

That is, to find the conditional probability $P(Non-fiction| 9th\ grade)$ .

Now, $P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

So, we get,

$P(Non-fiction| 9th\ grade)=\dfrac{(Non-fiction\bigcap 9th\ grade)}{P(9th\ grade)}\\\\P(Non-fiction| 9th\ grade)=\dfrac{8}{43}\\\\P(Non-fiction| 9th\ grade)=0.19$

<h3>Thus, the required probability is 0.19.</h3>

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3 years ago

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ycow [4]

Answer:

I need more information, meaning his formula.

Step-by-step explanation:

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3 years ago

Read 2 more answers