You share only one distribution, so we'll focus on that one: mean: 30; std. dev.: 4.
Draw a "standard normal curve." Draw a vertical line in the exact middle of your curve. Label this line "30." Now "one standard dev. above the mean" is 30+4=34; "two std. devs. above the mean is 30+4+4=38, or 30+8=38. "three std. devs. above the mean is 30+3(4) = 42.
Now work in the other direction. Start with the mean: 30. But now subtract the std. dev. (4) instead of adding it. You'll get 30-4=26. This is "1 std. dev. below the mean. Continue: find 2 and 3 std. devs. below the mean.
Answer:
just trying to get the points
Step-by-step explanation:
³/₁₀ ÷ 4
³/₁₀ ÷ ⁴/₁
³/₁₀ × ¹/₄
³/₄₀
Step-by-step explanation:
lim(n→∞) (2ⁿ / 2ⁿ⁺¹)
lim(n→∞) (2ⁿ / (2ⁿ × 2¹))
lim(n→∞) (1 / 2)
1/2
