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kkurt [141]
2 years ago
10

Answer this question and show all the necessary steps to solve.

Physics
1 answer:
Liula [17]2 years ago
4 0

Answer:

√ ae/ ap = √ mp/me 1/2

Explanation:

Mass of the electron = M (Given)

Mass of the proton = M (Given)

Time = t (Given)

<h3>Electrostatic force, FE = eE (for </h3><h3>both electron and proton)</h3>

But acceleration of electron, ae =FE/me whereas

acceleration of proton, ap = FE/mp

S = 1/2at²1 = 1/2apt²2

<h3>Therefore,</h3>

t2/t1= √ ae/ ap

t2/t1= √ ae/ ap = √ mp/me 1/2

<h3>Thus, the ratio is nearly equal to</h3><h3> = √ ae/ ap = √ mp/me 1/2</h3>

<h2>so, option D is correct</h2>
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Explanation:

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3 years ago
Describe the structure of an atom
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Explanation:

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3 years ago
1. A pendulum has a period of 3 seconds. What's its frequency? 2. A pendulum has a frequency of 0.25 Hz. What's its period? 3. A
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Answer:

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(2) 4 sec

(3) 2 sec, 0.5 Hz

Explanation:

(1) We have given time period of pendulum is 3 sec

So T = 3 sec

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(2) Frequency of the pendulum is given f = 0.25 Hz

Time period is equal to T=\frac{1}{f}=\frac{1}{0.25}=4sec

(3) It is given that a pendulum makes 10 back and forth swings in 20 seconds

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How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating at 5 km/hr?
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<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>

Given that ,

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  • Final Velocity of car = 0km / hr.
  • Acceleration = -5km/hr².

To Find :

  • Time taken to stop the car .

So , here use first equⁿ of motion which is ,

\boxed{\red{\bf\dag v = u + at }}

where ,

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Now , substituting the respective values ,

\tt:\implies v=u+at

\tt:\implies 0 = 44 + (-5)t

\tt:\implies -44 = -5t

\tt:\implies t=\dfrac{44}{5}

\underline{\boxed{\red{\tt \longmapsto Time\:\:=\:\:8.8hrs.}}}

\boxed{\green{\bf\pink{\dag} Hence\:time\:taken\:to\:stop\:the\:car\:is\:8.8hrs.}}

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Answer:

3 m/s east

Explanation:

I took a test a got it right

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