what is the closest to the order of magnitude of the energy rquired to split a nucleus in to its individual protons and neutrons
1 answer:
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Answer:
E = 12262 V/m
Explanation:
given,
Charge of the particle, q = +4.0 μC
mass of the ball, m = 5 g
Electric field, E = ?
Force due to weight
F = m g
Force due to electric field
F =q E
To balance the weight of particle both the forces must be equal
Electric field exerted on the ball will be equal to
m g = q E
E = 12262 V/m
Hence, the electric field acting in the particle is equal to E = 12262 V/m
Answer:
Explanation:
By using relation,
Speed of light = frequency × wavelength (in m)
An electron is emitted from a nucleus- State the effect this has on the charge of the nucleus
Answer:
an electron orbiting around the nucleus combines with a nuclear proton to produce a neutron, which remains in the nucleus, and a neutrino, which is emitted. As in positron emission, the nuclear positive charge and hence the atomic number decreases by one unit, and the mass number remains the same.
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