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snow_tiger [21]
3 years ago
6

In which condition the acceleration of a moving vehicle become zero​

Physics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Explanation:

When,the vehicle has uniform velocity, it's acceleration becomes zero

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Cognitive,emotional, and physical reasons why adolescents engage in riskier behavior
taurus [48]
Cognitive:
This is because teens tend to excrete more hormones when they are in their adolescent ages causing them to act in a riskier behavior.
Emotions:
Because of their feeling that they want to have freedom.
Physical:
Their hormones are affecting their actions.
8 0
3 years ago
A student on an amusement park ride moves in a circular path with a radius of 3.5 meters once every 8.9 seconds. What is the ave
Ulleksa [173]
Distance traveled by him = circumference of that circular path = 2πr = 2π(3.5)
= 7π = 7×3.14 = 21.98 m
time = 8.9 s  [ Given ]

Now, Average speed = distance / time
s = 21.98 / 8.9
s = 2.46 m/s

Hope this helps!
7 0
3 years ago
An ice skater starts with a velocity of 2.25 m/s in a 50.0 degree direction. After 8.33s, she is moving 4.65 m/s in a 120 degree
Mnenie [13.5K]

The y-component of the acceleration is 0.22 m/s^2

Explanation:

The y-component of the acceleration is given by

a_y = \frac{v_y-u_y}{t}

where

v_y is the y-component of the final velocity

u_y is the y-component of the initial velocity

t is the time elapsed

For the ice skater in this problem, we have:

u = 2.25 m/s is the initial velocity, in a direction \theta=50.0^{\circ}

v = 4.65 m/s is the final velocity, in a direction 120^{\circ}

t = 8.33 s is the time elapsed

The y-components of the initial and final velocity are:

u_y = u sin \theta = (2.25)(sin 50^{\circ})=1.72 m/s\\v_y = v sin \theta = (4.65)(sin 50^{\circ})=3.56 m/s

So the y-component of the acceleration is

a_y = \frac{3.56-1.72}{8.33}=0.22 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

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#LearnwithBrainly

7 0
3 years ago
A manometer is used to measure the air pressure in a tank. The fluid used has a specific gravity of 1.25, and the differential h
Sloan [31]

Answer:

77.88 lbm/ft³

Explanation:

Given,

Specific gravity, SG = 1.25

Density of water, ρ = 62.30 lbm/ft³

density of the fluid =

   = S.G x ρ_{water}

   = 62.30 x 1.25

   = 77.88 lbm/ft³

Density of the fluid is equal to 77.88 lbm/ft³

3 0
3 years ago
an object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object
emmainna [20.7K]

Answer:

The acceleration of the object is -30\ m/s^2

Explanation:

Given:

Initial velocity of object v_i = 200 feet/second

Final velocity of object v_f = 50 feet/second

Time of travel = 5 seconds

To calculate acceleration of the object we will find the rate of change of velocity with respect to time.

So, acceleration a is given by:

a=\frac{v_f-v_i}{t}

where v_f represents final velocity, v_i represents initial velocity and t is time of travel.

Plugging in values to evaluate acceleration.

a=\frac{50-200}{5}

a=\frac{-150}{5}

a=-30\ m/s^2

The acceleration of the object is -30\ m/s^2 (Answer). The negative sign shows the object is slowing down.

4 0
4 years ago
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