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Black_prince [1.1K]
2 years ago
5

Question 4 of 10

Chemistry
1 answer:
natka813 [3]2 years ago
8 0

Answer:

Stalactites - Hang from caves ceilings

Stalagmites - Grow from cave floors

Sinkholes - Collapsed caves

Speleothems - Cave features

Explanation:

Got it right :)

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Suppose that you add 26.7 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f Kf of 5.12 oC/m. With the a
kiruha [24]

From the calculation, the molar mass of the solution is 141 g/mol.

<h3>What is the molar mass?</h3>

We know that;

ΔT = K m i

K = the freezing constant

m = molality of the solution

i = the Van't Hoft factor

The molality of the solution is obtained from;

m = ΔT/K i

m = 3.89/5.12 * 1

m = 0.76 m

Now;

0.76 =  26.7 /MM/0.250

0.76 = 26.7 /0.250MM

0.76 * 0.250MM =  26.7

MM= 26.7/0.76 * 0.250

MM = 141 g/mol

Learn more about molar mass:brainly.com/question/12127540?

#SPJ12

5 0
2 years ago
Why the ph of glycine increases when 0.1 M NaOH is added dropwise​
shtirl [24]

Answer:

The acid-base reaction produces glycine reduction, and hence the increase of glycine pH.

Explanation:

The glycine is an amino acid with the following chemical formula:

NH₂CH₂COOH  

The COOH functional group is what gives the acid properties in the molecule.      

Hence, when NaOH is added to glycine an acid-base reaction takes place in which COOH reacts with the NaOH added:

NH₂CH₂COOH + OH⁻ ⇄ NH₂CH₂COO⁻ + H₂O

The glycine concentration starts to shift to its ion form (NH₂CH₂COO⁻) because of the reaction with NaOH, that is why the pH glycine increases when NaOH is added.  

Therefore, the acid-base reaction produces glycine reduction, and hence the increase of glycine pH.  

I hope it helps you!  

7 0
2 years ago
What two dose the transfer of light energy require
IrinaK [193]

Answer:

Magnetic fields  and Electric fields

Explanation:

3 0
2 years ago
2. Lysosomes operate within the cell bye to the
Marat540 [252]

Answer:

C

Explanation:

Lysosomes contain digestive enzymes which are used for digestion of food and dead organelles. It fuses with a vacuole which contain the targeted material(food or dead organelles) and digests the material inside it

3 0
3 years ago
Calculate the amount of water required to prepare 500g of 2.5% solution of sugar.
Snowcat [4.5K]

(i) We start by calculating the mass of sugar in the solution:

mass of sugar = concentration × solution mass

mass of sugar = 2.5/100 × 500 = 12.5 g  

Then now we can calculate the amount of water:

solution mass = mass of sugar + mass of water

mass of water =  solution mass - mass of sugar

mass of water = 500 - 12.5 = 487.5 g

(ii) We use the following reasoning:

If       500 g solution contains 12.5 g sugar

Then    X g solution contains 75 g sugar

X=(500×75)/12.5 = 3000 g solution

Now to get the amount of solution in liters we use density (we assume that is equal to 1):

Density = mass / volume

Volume = mass / density

Volume = 3000 / 1 = 3000 liters of sugar solution

8 0
3 years ago
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