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2 years ago

Whoever gets me right gets whatever they want

Chemistry

2 answers:

liberstina [14]2 years ago

7 0

Answer:

It is B my teacher said

Explanation:

Llana [10]2 years ago

6 0

Answer:

many nebulae are found inside of a single galaxy

Explanation:

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The formula for the table salt is NaCl. Is table salt ionic or covalent? Explain.

mel-nik [20]

Answer:

ionic

it is a mixture of a nonmetal and a metal which is what makes ionic compounds

covalent is a nonmetal and nonmetal

Explanation:

6 0

2 years ago

Determine whether the statement about identifying a halide is true: Regardless of any concentration of ammonium solution, the pr

frosja888 [35]

Answer:

False

Explanation:

The statement ; Regardless of any concentration of ammonium solution the precipitate of unknown halide after 0.1M AgNO3 will remain is FALSE

This is Because the remaining concentration of AgNO3 is dependent on the solubility of Ag⁺

3 0

2 years ago

Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +

Alika [10]

Answer:

$\Delta H$ for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

$C(graphite)+O_{2}(g)\rightarrow CO_{2}(g)$ $\Delta H_{1}= -393.5 kJ$

$2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l)$ $\Delta H_{2}= (2\times -285.8)kJ$

$CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)$ $\Delta H_{3}= 726.4 kJ$

---------------------------------------------------------------------------------------------------

$C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)$

$\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ$

4 0

3 years ago

Light is released when an excited electron moves from higher energy level back down to its lower, more stable energy level. The

kolbaska11 [484]

A0 emission as there is an increase in energy

5 0

2 years ago

Read 2 more answers

Write the chemical equation of the reaction with a change in colour

Lelu [443]

Answer:

(i) Change in colour (ii) Change in temperature (iii) Formation of precipitate

Explanation:

(i) Change in colour: Reaction between lead nitrate solution and potassium iodide solution. Pb(NO3)2(aq)+2KI → PbI2(s)+2KNO3(aq) In this reaction, colour changes from colourless to yellow. (ii)Change in temperature: Action of dilute sulphuric acid on zinc. Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2 In this reaction, heat is evolved (iii) Formation of precipitate: Action of barium chloride on sodium sulphate. BaCl2(aq) +Na2SO4(aq) → BaSO4(s) +2NaCl(aq) BaSO4(s)

8 0

2 years ago