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tia_tia [17]
2 years ago
14

7. Lli(s) + N₂(g) → 2 Liz Ncs)

Chemistry
1 answer:
timurjin [86]2 years ago
8 0

The number of mole of lithium, Li needed for the reaction is 3.2 moles (Option D)

<h3>Balanced equation </h3>

4Li + N₂(g) → 2Li₂N

From the balanced equation above,

2 moles of Li₂N were obtained from 4 moles of Li

<h3>How to determine the mole of lithium needed </h3>

From the balanced equation above,

2 moles of Li₂N were obtained from 4 moles of Li

Therefore,

1.6 moles of Li₂N will be obtained from = (1.6 × 4) / 2 = 3.2 moles of Li

Thus, 3.2 moles of Li are needed for the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

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A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
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Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

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m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

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