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2 years ago

12

Which reaction is reversible and could reach dynamic equilibrium?

2 answers:

alexandr1967 [171]2 years ago

8 0

Answer:

The correct answer is - option C. 3H2 + N2 = 2NH3

Explanation:

If in a chemical reaction the rate of the forward reaction and the rate of reverse reaction are equal, this is called dynamic equilibrium. Due to this equal rate of both side reactions, there is no change in the system. In this type of reaction, the concentration of reactants and products remain constant and the overall reaction is continuous.

Dynamic reactions can be reached by reversible reactions such as 3H2 + N2 = 2NH3 where the concentration of hydrogen and nitrogen and concentration of the ammonia remains constant and rate of the both side are equal.

Dmitrij [34]2 years ago

3 0

Answer:

3H2 + N2 = 2NH3

Explanation:

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Name a property copper has?

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Explanation:

It is malleable, ductile, and a good conductor of electricity and heat.

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A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.

Lubov Fominskaja [6]

Answer:

$Ag_2SO_4$

Explanation:

Formula for the calculation of no. of Mol is as follows:

$mol=\frac{mass\ (g)}{molecular\ mass}$

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

$mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol$

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

$mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol$

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

$mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol$

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

$Ag, \frac{0.05305}{0.02657} \approx 2$

$S, \frac{0.02657}{0.02657} \approx 1$

$O, \frac{0.10594}{0.02657} \approx 4$

Therefore, empirical formula of the compound = $Ag_2SO_4$

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