The required moles of water and anhydrous salt in the given reaction is 0.06 moles.
<h3>What is the relation between mass & moles?</h3>
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
- W = given mass
- M = molar mass
From the given data, mass of left water will be calculated by substracting the mass of CuSO₄ from the anhydrous salt as:
- Mass of Left water = 1.6 - 0.5 = 1.1 g
- Moles of left water = 1.1g / 18g/mol = 0.06 moles
Chemical reaction will be represented as:
CuSO₄.XH₂O → CuSO₄ + XH₂O
From the stoichiometry of the reaction it is clear that 0.06 moles of water is produced from 0.06 moles of anhydrous compound.
Ratio of the moles of water to salt = 0.06 / 0.06 = 1
So name of the compound CuSO₄.H₂O is copper sulfate monohydrate.
Hence, 0.06 moles of water as well as anhydrous compound is involved in the reaction and name of the obtained compound is copper sulfate monohydrate.
To know more about anhydrous compound, visit the below link:
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