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OleMash [197]
3 years ago
14

Which of the following is correct based on the given illustration?

Physics
1 answer:
VARVARA [1.3K]3 years ago
3 0
C and D are both possible.
But we have no idea which one is correct based on the given illustration, because you didn't give the illustration.

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The time period of the pendulum is affected by the acceleration due to gravity. The tension does not have any effect on the time period of the pendulum and also the mass of the bob does not effect the time period of the pendulum.

T = 2 \pi \sqrt{\frac{l}{g}}

Hence, if the gravity increases then the time period of the pendulum will decreases and it will swing faster.

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A rock falls off a cliff. How fast is the rock traveling vertically two seconds later?
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Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit
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$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

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Acceleration due to gravity at 2000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

  $= 673552 \times 10^{-8}$

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Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

  $= 3371 \times 153.86 \times 10^{-8}$

  = 5.18 m/s

Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

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A sound wave traveling eastward through air
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