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alisha [4.7K]
2 years ago
9

A long solenoid has a length of 0.67 m and contains 1700 turns of wire. There is a current of 5.5 A in the wire. What is the mag

nitude of the magnetic field within the solenoid?
Physics
1 answer:
docker41 [41]2 years ago
8 0

B = 17.5mT.

A solenoid is a coil formed by a wire (usually copper) wound into a cylindrical spiral shape capable of creating a magnetic field that is extremely uniform and intense inside, and very weak outside.

To calculate the magnetic field generated inside the solenoid through which a current flows is given by the equation:

B = μ₀nI

Where  μ₀ is the constant of magnetic proportionality of the vacuum (4π x 10⁻⁷T.m/A), n is the relation between the number of turns of wire and its length given by N/L and I is the current flowing through the solenoid.

Given a long solenoid of length 0.67m, 1700.00 turns of wire and a current flowing through the wire of 5.50A. Calculate the magnetic field inside the solenoid.

B = (4π x 10⁻⁷T.m/A)(1700turns/0.67m)(5.50A)

B = 0.0175T

B = 17.5mT

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8 0
1 year ago
2NaOH + H2SO4 → Na2SO4 + H2O
mina [271]
The equation is unbalanced because the number of hydrogen atoms and sodium atoms is not equal in the reactants and the products
6 0
3 years ago
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A cylinder with moment of inertia I about its center of mass, mass m, and radius r has a string wrapped around it which is tied
NARA [144]

Answer:

Explanation:

Let us study the downward  movement of cylinder which accelerates as well as rotates .

A)

If v be the linear downward velocity of cm of cylinder and ω be angular velocity of cylinder

v = ωr , when there is no slippage of string around cylinder.

B &C )

Total kinetic energy = Rotational + linear

= 1/2 Iω² + 1/2 m v²

1/2 x1/2 mr²ω² +1/2 m v²

= 1/4  mv² +1/2 m v²

= 3/4 m v²

For downward acceleration ,

mg - T = ma where T is tension in string.

Rotational movement

Torque = T x r

Tr = I α , I is moment of inertia and α is angular acceleration .

= I a/r

T = I a / r² , Putting this value of T in earlier equation

mg - I a / r²  = ma

a (I  / r² +m )= mg

a = mg /  (I  / r² +m )

For cylinders

I = .5 mr²

a = g / (.5 +1)

= g / 1.5

5 0
3 years ago
A coil with 150 turns and a cross-sectional area of 1.00 m2 experiences a magnetic field whose strength increases by 0.65T in 1.
aleksley [76]

Answer:

54.17volts

Explanation:

Induced emf in a coil placed in a magnetic field can be expressed as E = N¶/t where

N is the number of turns = 150turns

¶ is the magnetic flux = magnetic field strength (B) × area(A)

¶ = BA

B = 0.65T

A = 1.0m²

t is the time =1.8s

Substituting this value in the formula

E = NBA/t

E = 150×0.65×1.0/1.8

E = 54.17Volts

The induced emf in the coil is 54.17Volts

7 0
3 years ago
What is the wavelength in nm of a light whose first order bright band forms a
scoundrel [369]

The wavelength of the first order bright band light light is 714 nm .

Explanation:

We have to find the wavelength of the first order brightness of a light. Here we are using Huygen's principle of light.

The formula is

nλ =d sinθ

where, n is the order of maximum

            λ is the wavelength of light

            d is the distance between the lines on diffraction grating.

            θ is the angle.

For the given equation n is 1 because the problem states that the light forms 1st order bright band

  λ  is unknown.

d = \frac{1}{700,000} or 0.0000014 m

sin (30) = 0.5

so,

1(λ) = (0.0000014)(0.5)

     = 0.0000000714

     = 714 nm

Thus, The wavelength of the first order bright band light light is 714 nm .

3 0
3 years ago
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