Question

A proton moves north with a speed of 3 x 10^6 m/s. A 5 Tesla magnetic field is directed west. Determine the magnitude and direction of the magnetic field on the proton.

Answer 1

The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Magnitude of magnetic force on the proton

The magnitude of magnitude force on the proton is calculated as follows;

F = qvB sinθ

where;

• q is the charge of the proton
• v is the speed of the proton
• B is the magnitude of the magnetic filed
• θ is the angle between the field and speed

Substitute the given parameters and solve for the magnetic force.

F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)

F = 2.4 x 10⁻¹² N

Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Learn more about magnetic force here: brainly.com/question/13277365