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3 years ago

Identify the mixed number for the picture shown. A. 2 1⁄4 B. 11⁄2 C. 2 1⁄2 D. 3

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

5 0

Answer:

c. 2 1/2

Step-by-step explanation:

snow_lady [41]3 years ago

4 0

Answer:

A and C are mixed numbers

Step-by-step explanation:

A mixed number is a whole number with a fraction.
Correct Example: three and three-fourths is a mixed number.
Incorrect Example: Three is not a mixed number.

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How many feet long is the shadow of a 15-foot flagpole if a 5-foot woman standing at the base of the flagpole has a shadow that

Vikentia [17]

The height of flagpole is 12.5 feet.

Step-by-step explanation:

Given,

Height of woman = 5 foot

Shadow of woman = 6 feet

Ratio of height to shadow = 5:6

Shadow of flagpole = 15 foot

Height of flagpole = x

Ratio of height to shadow = x:15

Using proportion;

Ratio of height to shadow :: Ratio of height to shadow

$5:6::x:15\\$

Product of mean = Product of extreme

$6*x=15*5\\6x=75$

Dividing both sides by 6

$\frac{6x}{6}=\frac{75}{6}\\x=12.5$

The height of flagpole is 12.5 feet.

Keywords: ratio, proportion

Learn more about proportion at:

#LearnwithBrainly

8 0

3 years ago

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

8 0

3 years ago

Find the median of the given data if the mean is 4.5.5,7,7,8,x,5,4,3

timama [110]

Find the median of the given data. If the mean is 4.5...

5, 7, 7, 8,x,5,4,3 = x, 3, 4, 5, 5, 7, 7, 8

The median is 5. For the second part... The question is incomplete... “If the mean is 4.5...” Also, I have no idea if x should have been added or not. Even if it was, it doesn’t change the answer.

5 0

3 years ago

The graph below shows

Brilliant_brown [7]

Answer:

I am pretty sure that you just make the line steeper than the others, nothing specifically. I'm learning this in middle school and I would appreciate if someone else could specify on why

Step-by-step explanation:

6 0

3 years ago

The John Jay Theater Dept has tickets at $6 for adults, $4 for teachers, and $2 for students. A total of 280 tickets were sold f

OleMash [197]

Answer:

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

Step-by-step explanation:

Cost of tickets

Adults = $6

Teachers = $4

Students = $2

Total tickets sold = 280

Total revenue = $1010

Let

x = number of adults tickets

y = number of teachers tickets

z = number of students tickets

x + y + z = 280

6x + 4y + 2z = 1010

If the number of adult tickets sold was twice the number of teacher tickets

x = 2y

Substitute x=2y into the equations

x + y + z = 280

6x + 4y + 2z = 1010

2y + y + z = 280

6(2y) + 4y + 2z = 1010

3y + z = 280

12y + 4y + 2z = 1010

3y + z = 280 (1)

16y + 2z = 1010 (2)

Multiply (1) by 2

6y + 2z = 560 (3)

16y + 2z = 1010

Subtract (3) from (2)

16y - 6y = 1010 - 560

10y = 450

Divide both sides by 10

y = 450/10

= 45

y = 45

Substitute y=45 into (1)

3y + z = 280

3(45) + z = 280

135 + z = 280

z = 280 - 135

= 145

z = 145

Substitute the values of y and z into

x + y + z = 280

x + 45 + 145 = 280

x + 190 = 280

x = 280 - 190

= 90

x = 90

Therefore,

number of adults tickets sold = x = 90

number of teachers tickets = y = 45

number of students tickets = z = 145

5 0

4 years ago