Answer:
Ecosystems have lots of different living organisms that interact with each other. The living organisms in an ecosystem can be divided into three categories: producers, consumers and decomposers. They are all important parts of an ecosystem. Producers are the green plants.
Explanation:
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NH3 = water (it is actually a water soluble gas)
C6H14 = CCl4 (C6H14 won't mix with water at all)
Na2S = water (Na2S is a salt. Salts dissolve best in water)
Br2 = CCl4, but it will also dissolve in water.
Answer:
the statement is or are true for all chemical reaction is false
Explanation:
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Answer:
Mole fraction for solute = 0.1, or 10%
Molality = 6.24 mol/kg
Explanation:
22.3% by mass → In 100 g of solution, we have 22.3 g of HCOOH
Mass of solution = 100 g
Mass of solute = 22.3 g
Mass of solvent = 100 g - 22.3g = 77.7 g
Let's convert the mass to moles
22.3 g . 1mol/ 46 g = 0.485 moles
77.7 g. 1mol / 18 g = 4.32 moles
Total moles = 4.32 moles + 0.485 moles = 4.805 moles
Xm for solute = 0.485 / 4.805 = 0.100 → 10%
Molality → mol/ kg → we convert the mass of solvent to kg
77.7 g. 1 kg / 1000g = 0.0777 kg
0.485 mol / 0.0777 kg = 6.24 m
Answer:
3.93 mol
Explanation:
The balanced equation is given as;
2 Fe₂S₃+ 9 O₂ --> 2 Fe₂O₃ + 6 SO₂
From the reaction;
2 mol of Fe₂S₃ reacts with 9 mol of O₂ to form 6 mol of 6 SO₂
This means;
1 mol of Fe₂S₃ requires 9/2 mol of O₂
Also,
1 mol of O₂ requires 1/9 mol of Fe₂S₃
In the question, we have;
1.31 moles of Fe2S3 and 22.8 moles of O2
The limiting reactant which determine how much of the product formed is; Fe₂S₃ because O₂ is in excess.
The relationship between Fe₂S₃ and SO₂ is;
2 mol Fe₂S₃ produces 6 mol of SO₂
1.31 mol of Fe₂S₃ would produce x mol ?
2 = 6
1.31 = x
x = 6 * 1.31 / 2 = 3.93 mol
