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ddd [48]
2 years ago
8

If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the

balloon is the final volume is 74,000 m3.
Chemistry
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

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Answer:

0.00471 grams H₂O

Explanation:

To determine the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

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The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".

Q = 0.709 J                            c = 4182 J/g°C

m = ? g                                   ΔT = 0.036 °C

Q = mcΔT                                                    <----- Equation

0.709 J = m(4182 J/g°C)(0.036 °C)            <----- Insert values

0.709 J = m(150.552)                                 <----- Multiply 4182 and 0.036

0.00471 = m                                              <----- Divide both sides by 150.552

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