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ddd [48]
2 years ago
8

If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the

balloon is the final volume is 74,000 m3.
Chemistry
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

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Answer:

6.4 L

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P₁V₁ = P₂V₂

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P₁V₁ = P₂V₂                                                    <----- Boyle's Law

(3.2 atm)(2.0 L) = (1.0 atm)V₂                        <----- Insert values

6.4 = (1.0 atm)V₂                                           <----- Simplify left side

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Using integrated rate law for first order kinetics as:

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[A_0] is the initial concentration

Given that:

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Applying in the above equation, we get that:-

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-0.00012t=\ln \left(\frac{1}{4}\right)

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7 0
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Answer:

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6 0
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