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2 years ago

Please help me on #2 giving BRAINLIEST!

Chemistry

1 answer:

Amiraneli [1.4K]2 years ago

3 0

Answer:

basic

Explanation:

because H is hydrogen

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How many square centimeters are in an area of 8.50 inch^2

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Explanation:

Given parameters:

Dimension = 8.5in²

we are to convert from in² to cm²

in² = in x in

cm² = cm x cm

1 in = 2.54cm

Using dimensional analysis;

8.5in² x $\frac{2.54cm}{1in} x \frac{2.54cm}{1in}$

= 54.84cm²

We solved this problem using dimensional analysis where we multiplied the unit with 1.

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H₂O₂ + 2FeSO₄ + H₂SO₄ → Fe₂(SO₄)₃ + 2H₂O

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3 years ago

The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?

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Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

$K_a\times K_b=K_w$

$K_b$ for sodium formate is $K_b=\frac {K_w}{K_a}$

Given that:

$K_a$ of formic acid = $1.8\times 10^{-4}$

And, $K_w=10^{-14}$

So,

$K_b=\frac {10^{-14}}{1.8\times 10^{-4}}$

$K_b=5.5556\times 10^{-11}$

Concentration = 0.35 M

HCOONa ⇒ Na⁺ + HCOO⁻

Consider the ICE take for the formate ion as:

HCOO⁻ + H₂O ⇄ HCOOH + OH⁻

At t=0 0.35 - -

At t =equilibrium (0.35-x) x x

The expression for dissociation constant of sodium formate is:

$K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}$

$5.5556\times 10^{-11}=\frac {x^2}{0.35-x}$

Solving for x, we get:

x = 0.44×10⁻⁵ M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

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