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weeeeeb [17]
3 years ago
10

Describe how the terms reactant, product and chemical change relate?

Chemistry
1 answer:
alukav5142 [94]3 years ago
8 0
They all have to do with science. 
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De que factores dependen la constante de equilibrio ​
8_murik_8 [283]

Answer:

La constante de equilibrio (K) se expresa como la relación entre las concentraciones molares (mol/l) de reactivos y productos. Su valor en una reacción química depende de la temperatura, por lo que ésta siempre debe especificarse.

Explanation:

4 0
3 years ago
Which industry would most likely be affected if coal recourses were depleted.
Marat540 [252]
The answer is Power production
6 0
3 years ago
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Solubility
Inga [223]

Non electrolytes are Pentacarbon decahydride, Phosphorus pentachloride, Glucose.

<u>Explanation:</u>

Non electrolytes do not exist as ions in aqueous solution. Since it does not get dissociated into ions, these non electrolytes do not conduct electricity when it is dissolved or it is heated or melted.

Pentacarbon decahydride is a non electrolyte.

Magnesium chloride is an electrolyte.

Copper phosphate is an electrolyte

Sulfur trioxide is an electrolyte.

Aluminum oxide is an electrolyte

Phosphorus pentachloride do not get dissociated into its ions so it is a non-electrolyte.

Glucose gets dissolved in water but do not dissociate into ions, so it is a non electrolyte.

5 0
4 years ago
All of the atoms of argon have the same?
JulijaS [17]
2 is right i would think
4 0
3 years ago
Read 2 more answers
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

2*n_{acid}=n_{base}

And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

Best regards.

5 0
3 years ago
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