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sveta [45]
4 years ago
15

how many of the following elements have 2 unpaired electrons in the ground state? C, O, Ti, Si a) 1 b) 3 c) 4 d) 2

Chemistry
2 answers:
lbvjy [14]4 years ago
7 0
<h3><u>Answer;</u></h3>

c) 4

<h3><u>Explanation;</u></h3>
  • An unpaired electron is an electron that occupies an orbital of an atom singly, rather than as part of an electron pair.
  • To find out if the electrons inside an orbital are paired or not you need to find out the maximum electrons the subshell can hold. If the electrons in the subshell are less than the maximum electrons it can hold the electron in any of the orbital can be unpaired.
  • Oxygen, O, has two unpaired electrons.
  • Carbon, C, has two unpaired electrons
  • Ti and Si have two unpaired electrons

Nady [450]4 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of carbon is 6 and its electronic configuration is 1s^{2}2s^{2}2p^{2}.

Atomic number of oxygen is 8 and its electronic configuration is 1s^{2}2s^{2}2p^{4}.

Atomic number of titanium is 2 and its electronic configuration is [Ar]4s^{2}3d^{2}.

Atomic number of silicon is 14 and its electronic configuration is [Ne]3s^{2}3p^{2}.

Therefore, we can conclude that out of the given options all the 4 elements have 2 unpaired electrons in the ground state.

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Explanation:

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Use the definition of molarity to calculate the concentration of 12.34 g of CaSO4 completely dissolved in water, with a solution
Ede4ka [16]

Answer:

[CaSO₄] = 36.26×10⁻² mol/L

Explanation:

Molarity (M) → mol/L → moles of solute in 1L of solution

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250 mL . 1L/1000 mL = 0.250L

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8 0
4 years ago
A or B i need help fast
Bezzdna [24]

Answer: I would go with B

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5 0
3 years ago
5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?
Margaret [11]

Answer:

\boxed {\boxed {\sf 2.8 \ m }}

Explanation:

The formula for molality is:

m=\frac{moles \ of \ solute}{kg \ of \ solvent}

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moles= 0.210 \ mol \\kilograms = 0.075 \ kg

Substitute the values into the formula.

m= \frac{ 0.210 \ mol }{0.075 \ kg}

Divide.

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3 years ago
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