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Goshia [24]
2 years ago
14

What would the charge on KAt be?

Chemistry
1 answer:
Veseljchak [2.6K]2 years ago
5 0

The overall charge of the given compound of potassium and Arsenic is zero (0).

<h3>What is the charge of an atom?</h3>

An atom consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. When the number of protons exceed the number of electrons, the atom will positively charged and it will be negatively charged if the number of electrons exceed the number of protons.

For the given compound;

  • KAs; As (Arsenic = -3) + K (potassium = +3)
  • KAs overall charge = -3 + 3 = 0

Thus, the overall charge of the given compound of potassium and Arsenic is zero (0).

Learn more about charge here: brainly.com/question/25922783

#SPJ1

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How many grams of carbon are contained in one mole of<img src="https://tex.z-dn.net/?f=C_%7B3%7DH_%7B8%7D" id="TexFormula1" titl
NNADVOKAT [17]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \:36 \:\: g

____________________________________

\large \tt Explanation \: :

The given compound has 3 carbon atoms, so in 1 mole of that compound, there will be 3 moles of carbon atoms.

Mass of each mole of carbon atoms = 12 g

For 3 mole carbon atoms, it will be 12 × 3 = 36 grams

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0
2 years ago
Help please
Mekhanik [1.2K]

Answer:

it's the regolith

hope this helps you

C Horizon - Also called regolith: the layer beneath the B Horizon and above the R Horizon. It consists of slightly broken-up bedrock. Plant roots do not penetrate into this layer; very little organic material is found in this layer. R Horizon - The unweathered rock (bedrock) layer that is beneath all the other layers.

7 0
3 years ago
4Cr(s)+3O2(g)→2Cr2O3(s) calculate how many grams of the product form when 21.4 g of O2 completely reacts
weqwewe [10]

Answer:

= 67.79 g

Explanation:

The equation for the reaction is;

4Cr(s)+3O2(g)→2Cr2O3(s)

The mass of O2 is 21.4 g, therefore, we find the number of moles of O2;

moles O2 = 21.4 g / 32 g/mol

                =0.669 moles

Using mole ratio, we get the moles of Cr2O3;

moles Cr2O3 = 0.669 x 2/3

                       =0.446 moles

but molar mass of Cr2O3 is 151.99 g/mol

Hence,

The mass Cr2O3 = 0.446 mol x 151.99 g/mol

                            <u> = 67.79 g </u>

6 0
3 years ago
Suppose an egyptian mummy is discovered in which the amount of​ carbon-14 present is only about oneone​-fifthfifth the amount fo
poizon [28]

We are given the following equation:

y = y0 e^-0.0001216 t

where y = 1/5 y0, y0 is the original amount

So solving for time t:

1/5 y0= y0 e^-0.0001216 t

t = 13,235.51 years

 

So the human died about 13235.5 years ago

3 0
3 years ago
(( PLEASE HELP QUICK ))Which expression can be used to calculate the ratio of the rate of effusion of gas A to the rate of effus
borishaifa [10]

Answer:

The square root of the molar mass of B ÷ the square root of the molar mass of A  

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases A and B, the ratio of their rates of effusion is

\dfrac{r_{\text{A}}}{r_{\text{B}}} = \sqrt{\dfrac{M_{\text{B}}}{M_{\text{A}}}}

3 0
3 years ago
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